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belka [17]
3 years ago
13

How to solve 9 and 10?

Mathematics
1 answer:
netineya [11]3 years ago
4 0

Answer:

Step-by-step explanation:

Simply, substitute the coordinates (x,y), in the equation given!

9. 5 = 3(-3)/4 -4

   5 = -9/4 -4

   5 = -25/4

The LHS is not equal to RHS, this means that the given coordinate doesn't exist on the linear function given!

10.  5(10)-6(7) =18

      50-42 =18

              8=18

Same as above, it doesn't work!

Hope this helps!

If you think I helped, mark brainliest! Would really appreciate!

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Solve.
ZanzabumX [31]

Answer:

ok the answer is C

Step-by-step explanation:

1.75*4=7

.75*2=1.5

7+1.5=8.50

8 0
3 years ago
Read 2 more answers
For the sequence 3n - 1, generate the first three terms.
Hunter-Best [27]
3n - 1

When n = 1,

3n - 1 = 3*1 - 1 = 3 -1 = 2

When n = 2,

3n - 1 = 3*2 - 1 = 6 -1 = 5

When n = 3,

3n - 1 = 3*3 - 1 = 9 -1 = 8

Hence, the first three terms are 2, 5 and 8.
5 0
3 years ago
Please help?!
Anton [14]

Answer:

Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

TP = 20 ft

In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider  the ratio of the sides

\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}            ..............( 1 )

\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}            ..............( 2 )

\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}            ..............( 3 )

So By equation ( 1 ), ( 2 ) and  ( 3 ) we get

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Now in Δ PQT  and Δ QRS we have

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proved

8 0
3 years ago
Proper angle for a ladder is about 75° from the ground. Suppose you have a 10 foot ladder. How far from the house should you pla
Alja [10]

Answer:

The base of the ladder is 2.58 m.

Step-by-step explanation:

Given that,

The angle of elevation for a ladder from the ground is 75°.

The length of a ladder, H = 10 foot

We need to find the distance from the house should you place the base of the latter. Let the base of the ladder is b. Using trigonometry,

\cos\theta=\dfrac{B}{H}\\\\B=H\times \cos\theta\\\\B=10\times \cos(75)\\\\B=2.58\ m

So, the base of the ladder is 2.58 m.

8 0
3 years ago
Can you help me with this please???
Dahasolnce [82]

Answer:

c?

Step-by-step explanation:


8 0
4 years ago
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