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4 years ago

B= 3x + 4g for a = -9 and b = 12

Mathematics

2 answers:

ella [17]4 years ago

8 0

B3x+2=32 and 5 with a but b=32c

zalisa [80]4 years ago

6 0

Answer:

B3x+2=32 and 5 with a but b=32c

Step-by-step explanation:

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Maggie volunteered to bake a cake she decided to double the recipe if the original recipe calls for 3/4 cup brown sugar how much

zlopas [31]

Answer:

3/2

Step-by-step explanation:

3/4 * 2 = 6/4 = 3/2

7 0

4 years ago

Design minimal 2-level AND-OR and NAND-NAND realizations of the following logic function. Draw circuit diagrams of your realizat

Delicious77 [7]

Answer:

Realization :

since there are 3-variable. Therefore 2ⁿ = 2³ = 8

From the attached solution, f(x,y,z) = y' + xz'

also' see the circuit diagrams of my realizations of AND-OR and NAND-NAND

Step-by-step explanation:

See attached picture for minimal 2-level AND-OR and NAND-NAND of the logic function.

f(x,y,z) = y' + xz' was designed from the function f(x,y,z) = Σm(0,1,4,5,6)

Then, minimal 2-level AND-OR was designed and after was NAND-NAND designed as well.

5 0

3 years ago

A ratio of shirts to belts in a persons closet is 3:2 if there are 24 shirts in the closet how many belts are in the closet?

Lera25 [3.4K]

Answer: there are 16 belts.

Step-by-step explanation: because

6 0

3 years ago

Read 2 more answers

Please help!!! Verify which of the following are identities.

Ierofanga [76]

Answer:

First one

Step-by-step explanation:

None of the equations are identities

4 0

3 years ago

Mystery Boxes: Breakout Rooms

ollegr [7]

Answer:

$\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}$

Step-by-step explanation:

Given

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}$

Required

Fill in the box

From the question, the range is:

$Range = 60$

Range is calculated as:

$Range = Highest - Least$

From the box, we have:

$Least = 1$

So:

$60 = Highest - 1$

$Highest = 60 +1$

$Highest = 61$

The box, becomes:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

From the question:

$IQR = 20$ --- interquartile range

This is calculated as:

$IQR = Q_3 - Q_1$

$Q_3$ is the median of the upper half while $Q_1$ is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}$

Upper half

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

The quartile is calculated by calculating the median for each of the above halves is calculated as:

$Median = \frac{N + 1}{2}th$

Where N = 7

So, we have:

$Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th$

So,

$Q_3$ = 4th item of the upper halves

$Q_1$ = 4th item of the lower halves

From the upper halves

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

We have:

$Q_3 = 32$

$Q_1$ can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

$IQR = Q_3 - Q_1$

Where $Q_3 = 32$ and $IQR = 20$

So:

$20 = 32 - Q_1$

$Q_1 = 32 - 20$

$Q_1 = 12$

So, the lower half becomes:

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}$

From this, the updated values of the box is:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$