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Svetach [21]
3 years ago
7

Which graph does NOT represent a function?

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

The circle graph does not represent a function because it doesn't pass the vertical line test.

Step-by-step explanation:

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Solve for x. Round to the nearest tenth of a degree, if necessary
Fynjy0 [20]

Step-by-step explanation:

here's the answer to your question

8 0
3 years ago
In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence
Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

\hat p =\frac{12}{300}=0.04

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The critical value of <em>z</em> for 95% confidence level is,

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

6 0
3 years ago
Determine if the situation is a percent INCREASE or DECREASE
VashaNatasha [74]

Answer: Decrease

Step-by-step explanation:

3 0
3 years ago
A number is selected randomly from the integer from 10to30 what is the probability of picking a multiple of 4or5​
arlik [135]

Answer:

\frac{3}{7}

Step-by-step explanation:

Start by finding how many integers there are from 10-30...

30-10+1=20+1=21

Note we have to add 1 since it is inclusive.

Now, let's find how many multiples of 4 or 5 there are from 10-30...

4*3=12

4*4=16

4*5=20

4*6=24

4*7=28

5*2=10

5*3=15

5*4=20

5*5=25

5*6=30

5+5-1=9

Note we have to subtract 1 since 20 is counted twice.

The probability would be...

\frac{Multiples\ of\ four\ and\ five\ from\ 10-30}{Amount\ of\ integers\ between\ 10-30}=\frac{9}{21}=\frac{3}{7}

6 0
2 years ago
Evaluate the following expression:
grigory [225]

Answer:

5.25

Step-by-step explanation:

7 0
3 years ago
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