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2 years ago

The lines shown below are parallel. If the green line has a slope of -1/2 what is

Mathematics

1 answer:

Arisa [49]2 years ago

5 0

Answer:

By definition, two parallel lines must have the same slope. Therefore, the slope of the red line is the same as that of the green line.

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Which fraction is equivalent to negative 5 over 9?

o-na [289]

-5/9

multiply by -1/-1

(-5*-1)/ (9*-1)

5/(-9)

Answer = 5 over negative 9

7 0

2 years ago

The sum of two numbers is twenty-four. The difference of the two numbers is four.

RSB [31]

Answer:

$x + y = 24$

$x - y = 4$

Now, add these two equations.

You get,

$2x = 28$

$x = \frac{28}{2}$

$x = 14$

Given,

$x + y = 24$

$14 + y = 24$

$y = 24 - 14$

$y = 10$

You can test this to the other equation as well.

$x - y = 4$

$14 - 10 = 4$

Hence, the two numbers are 14 and 10.

3 0

2 years ago

A ball is hurled in the air such that its horizontal (x) and vertical (y) shifts are given by the functions x(t) = 20t and y(t)

Viefleur [7K]

x(t) = 20t

y(t) = 40t - 5t^2

Since we are only interested in comparing the two at time t = 5 seconds, we plug in 5 everywhere we see the variable t and then compare x and y

x(5) = 20(5) becomes x(5) = 100

y(5) = 40(5) - 5(5)^2 becomes y(5) = 200 - 125 and then y(5) = 75

The ratio of y to x can be expressed as: y/x, so we can say the ratio is equal to 75/100 or 0.75

Answer: 0.75

7 0

3 years ago

Function or not a function

Aliun [14]

Answer:

not a function

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Special Right Trianglws

Masteriza [31]

Answer:

x = $2\sqrt7$

y = $2\sqrt7$

Step-by-step explanation:

Hello!

This is a right isosceles triangle (45°-45°-90°). You can solve for the missing angle by simply subtracting 45° and 90° from 180° (sum of angles in a triangle equals 180°)

Since the triangle is isosceles, x and y are congruent because they are the legs opposite to the congruent angles.

In a right isosceles triangle, the hypotenuse is always the measure of one leg multiplied by $\sqrt2$ .

So, let's use leg y, $y\sqrt2 = 2\sqrt{14}$

Solve for y:

$y\sqrt2 = 2\sqrt{14}\\\\y = $\frac{2\sqrt{14}}{\sqrt2}$\\\\y = 2\sqrt7$

y = $2\sqrt7$ , which means that x is also $2\sqrt7$

3 0

2 years ago