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3 years ago

In the diagram below m DEF = 115°Find the measure of GEF

Mathematics

1 answer:

Stels [109]3 years ago

6 0

115 - 40 = 75
Because 115 is the total and your getting rid of the 40 other degrees in the 115

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6th grade math<br><br> help on numbers 4 5 6 plz help

mario62 [17]

Answer:

4) 6 students

5) 7 fewer students

6) No, you can not tell from the frequency table how many students ran a mile in exactly 12 minutes.

Step-by-step explanation:

4) you’d look at the row from 8:00-8:59.

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Hope this helped, sorry if I’m wrong on #6 ;)

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3 years ago

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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

8 0

3 years ago

In the diagram below m DEF = 115°Find the measure of GEF​

In the diagram below m DEF = 115°Find the measure of GEF