Summaation of a sequence
or see a smaller scale
from 1 to 10
notice
1+10=11
2+9=11
etc
5+6=11
10/2=5
there are 5 pairs
5*11=55
so
1 to 100
1+100=101
2+99=101
...
50+51=101
100/2=50
there ar 50 pairs
50 times 101=5050
the sum is 5050
Answer:
option c is the correct answer
Answer:
72,90
Step-by-step explanation:
Since 9 is the biggest number so list multiples of 9 between 55- 101 range.
Which are 63, 72, 81, 90, 99. Any number that is a multiple of 9 is a multiple of 3 because 3x 3 = 9. 9 is a multiple of 3.
Any even number is a multiple of 2.
Only 72 and 90 are even numbers.
So 72 and 90 are numbers divisible by 2, 3, 9.
Answer:
11
Step-by-step explanation: