All categories

3 years ago

Please help thanks so much

Mathematics

1 answer:

Goshia [24]3 years ago

6 0

Answer:

y = (-4/3)*x + 7

Step-by-step explanation:

The point-slope form of the equation of a line is: y = a*x + b

In the above equation, a is the slope of the line representing the equation in the graph and y is the function of x [y = y(x)]

The given line has a slope of -4/3, so that a = -4/3

=> The equation of this line has a form as following: y = (-4/3)*x + b (1)

As the line passes through the point (9; -5) (in which: x = 9; y = -5). Replace x =9 and y = -5 into the equation (1), we have:

y = (-4/3)*x + b

=> -5 = (-4/3)*9 + b

=> -5 = -12 + b

=> b = 7

So that the equation in point-slope form of the given line is:

y = (-4/3)*x + 7

You might be interested in

Add:(3x2 - 5x + 6) + (9 - 8x - 4x2)

finlep [7]

You can see by the image how did I get the answer

3 0

3 years ago

Evaluate the expression 3(7 + 4)2 − 14 ÷ 7. 50 361 363 586

Kipish [7]

It appears that none of your option choices are correct,, are you sure you copied them right ? I will show you how to solve this and how I got my answer.
The first step for solving this is to add the numbers in the parenthesis.
3 × 11 × 2 - 14 ÷ 7
Divide -14 by 7.
3 × 11 × 2 - 2
Divide the first 3 numbers together.
66 - 2
Subtract the numbers together to get your final answer.
64
Let me know if you have any further questions.
:)

4 0

3 years ago

Read 2 more answers

Find the domain of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E3-16x%7D" id="TexFormula1" title="\sqrt{x^3

Anon25 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

$f\left(x\right)=\sqrt{x^3-16x}$

We know that the domain of the function is the set of input or arguments for which the function is real and defined.

In other words,

Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

$x^3-16x\ge 0$

as x³ - 16x ≥ 0

$\left(x+4\right)\left(x-4\right)\ge \:0$

Thus, identifying the intervals:

$-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4$

Thus,

The domain of the function f(x) is:

$x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}$