Question

10 POITNTS FOR CORRECT ANSWER!! find perimeter of shape to nearest tenth cm

Answer 1

use sin to sing the other side (8.5) and then do 8.5+8.5+12+12=41

Answer 2

Answer:

The perimeter of the shape is 41.0 cm

Step-by-step explanation:

We know that both the bottom base and the top base are 12 cm.

We can separate this shape into two congruent triangles and one square.

We can also know that the angle of the other side of the triangle is 45° as

$180-45=45$

As each of these triangles are isosceles triangles, the length of the lower side is 6 cm as well.

This means by using the Pythagorean theorem we can find the length of the hypotenuse of this triangle.

$a^2+b^2=c^2\\\\c=\sqrt{a^2+b^2} \\\\c=\sqrt{6^2+6^2}\\\\c=\sqrt{36+36}\\\\c=\sqrt{72}$

The base of the triangle is 6 cm, so we can find the length of the base of the square by finding the difference of 12 and 6, which is 6.

This means that the equation for the perimeter would be

$6+6+\sqrt{72} +6+6+\sqrt{72} \\\\24+2\sqrt{72} =40.970\\\\41.0$