Ask question

Ask question

All categories

3 years ago

13

Find mZXZY (8x - 1) (5x + 11)

1 answer:

OLga [1]3 years ago

3 0

Answer:

Can you give options because we unable to answer

You might be interested in

The coordinates of the vertices of ΔMDT are M (4, −3),D (−6, −1), and T (7, −8). Identify the perimeter of ΔMDT. Round each side

Ganezh [65]

$M=(4,-3)\qquad D=(-6,-1)\qquad T=(7,-8)\\\\\\
|MD|=\sqrt{\big(-6-4\big)^2+\big(-1-(-3)\big)^2}=\sqrt{\big(-10\big)^2+\big(-1+3\big)^2}=\\\\=\sqrt{100+2^2}=\sqrt{104}\approx\boxed{10.2}\\\\\\\\
|DT|=\sqrt{\big(7-(-6)\big)^2+\big(-8-(-1)\big)^2}=\sqrt{\big(7+6\big)^2+\big(-8+1\big)^2}=\\\\=\sqrt{13^2+(-7)^2}=\sqrt{169+49}=\sqrt{218}\approx\boxed{14.8}\\\\$

$|TM|=\sqrt{\big(4-7\big)^2+\big(-3-(-8)\big)^2}=\sqrt{\big(-3\big)^2+\big(-3+8\big)^2}=\\\\=\sqrt{9+5^2}=\sqrt{9+25}=\sqrt{34}\approx\boxed{5.8}$

So the perimeter:

$P_{\Delta MDT}=|MD|+|DT|+|TM|\approx10.2+14.8+5.8=\boxed{30.8}$

Answer C.

4 0

4 years ago

What is the common ratio between successive terms in the sequence? 2, –4, 8, –16, 32, –64, ...

sergeinik [125]

2×-2=-4
-4 × -2 = 8
8 × -2 =-16
-16×-2 =32
32 ×-2 = -64.
therefore the answer is -2.

8 0

3 years ago

Read 2 more answers

Anyone watch anime? If you do plz answer lol, have a good day :)

wlad13 [49]

Answer:

MYSTREET AND MY INNER DEMONS YES

Step-by-step explanation:

watch them

4 0

3 years ago

The table shows the hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale. Grade 7 Grade 8 20 21 15

Naddika [18.5K]

Answer:

1. The interquartile range for the grade 7 data is 6.

2. The interquartile range for the grade 8 data is 6.

3. The difference of the medians of the two data sets is 2.

4. The difference is about 1/3 times the interquartile range of either data set.

Step-by-step explanation:

The hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale is given by the following table.

Grade 7 Grade 8

20 21

15 29

30 14

24 19

18 24

21 25

The data set for grade 7 is

20, 15, 30, 24, 18, 21

Arrange the data in ascending order.

15, 18, 20, 21, 24, 30

Divide the data in four equal parts.

(15), 18, (20), (21), 24,( 30)

$Q_1=18, Median=\frac{20+21}{2}=20.5, Q_3=24$

The interquartile range for the grade 7 data is

$IQR=Q_3-Q_1=24-18=6$

Therefore the interquartile range for the grade 7 data is 6.

The data set for grade 8 is

21, 29, 14, 19, 24, 25

Arrange the data in ascending order.

14, 19, 21, 24, 25, 29

Divide the data in four equal parts.

(14), 19, (21), (24), 25, (29)

$Q_1=19, Median=\frac{21+24}{2}=22.5, Q_3=25$

The interquartile range for the grade 8 data is

$IQR=Q_3-Q_1=25-19=6$

Therefore the interquartile range for the grade 8 data is 6.

The difference of the medians of the two data sets is

$D=22.5-20.5=2$

Therefore the difference of the medians of the two data sets is 2.

Let the difference is about x times the interquartile range of either data set.

The IQR of each data is 6.

$D=x(IQR)$

$2=x(6)$

$\frac{2}{6}=x$

$\frac{1}{3}=x$

Therefore the difference is about 1/3 times the interquartile range of either data set.

8 0

3 years ago

To avoid a storm, a passenger-jet descended 0.44 mile in 0.8 minute. What was the plan’s average change of altitude per minute?

sdas [7]

Answer:

0.55

Step-by-step explanation:

.44 divided by .8

7 0

3 years ago