Answer:
You need to provide the diagram with the question for me to effectively help you solve this I am sorry but I cant properly help right now.
Step-by-step explanation:
Hi! I don’t know what any of this means but I hope you have an amazing day and I hope god/allah/etc. blesses you :)
sorry I couldn’t answer
Step-by-step explanation:
3v/7=6
3v=6×7
3v=42
v=42/3
v=14
hope it helps.
Answer:
11 is a whole number in between 94/9 and square root of 144 (which is 12 btw)
Step-by-step explanation:
Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)