Answer:
Step-by-step explanation:
Since you didn't state what you're looking for, I will lost out all the angles in the picture instead.
Given that
∠CEF = 150°
∠ECA = 32°
∠CEA = 180 - ∠CEF(angles in a straight line)
∠CEA = 180 - 150
∠CEA = 30°
∠EAC = 180 - ∠CEA - ∠ECA(angles in a triangle)
∠EAC = 180 - 30 - 32
∠EAC = 118°
∠CAB = 180 - ∠EAC(angles in a triangle)
∠CAB = 180 - 118
∠CAB = 62°
∠ACB = ∠CEA = 30°(similar angles)
∠ABC = 180 - ∠CAB - ∠ACB(angles in a triangle)
∠ABC = 180 - 62 - 30
∠ABC = 88°
∠ECB = ∠ECA + ∠ACB(angles in a triangle)
∠ECB = 32 + 30
∠ECB = 62°
∠CEA + ∠ECB + ∠ABC = 180
30 + 62 + 88 = 180°.
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Answer:
$6,000
Step-by-step explanation:
10/100 = x/600
= (600 * 100)/10
= 600 * 10
so you will have to convert it to slope intercept form which is y=mx+B so you will have to isolate the y
6y+8x=24 subtract 8x to both sides
6y=-8x+24
divide 6 by both sides
y= -8/6x + 4
simplify
y= -4/3x + 4
the slope of the line is -4/3
X + (x + 2)
x + 2 + 3x = 234 combine like terms
4x + 2 = 234 subtract two to isolate x
4x = 232 divide by four
x = 58
The two numbers are 58 and 60.
The greatest common factor of the two expressions given as in the task content is; 3v².
<h3>What is the greatest common factor of the two expressions given?</h3>
It follows from the task content that the terms whose greatest common factor are to be determined are: 15v³ and 12 v².
15v³ and 12v²
= 3v²(5v) and 3v²(4)
= 3v²(5v) and (4)
Consequently, in a bid to factorise the two expressions by means of their greatest Common factor, the greatest common factor can be determined as; 3v².
The correct answer choice which therefore represents the greatest common factor as required in the task content is; 3v².
Read more on greatest common factor;
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