Answer:
Julian has <em>16 dimes</em> and <em>6 quarters</em>
Step-by-step explanation:
Let's suppose Julian has q quarters and d dimes
The total coins are 22, that is
q+d=22
q=22-d [1]
The total amount of money he has is 310 cents which are made of 10d dimes and 25q quarters
10d+25q=310
Simplifying by 5
2d+5q=62
Using the relation [1]
2d+5(22-d)=62
2d+110-5d=62
3d=48 => d=16
q=22-16 = 6
So Julian has 16 dimes and 6 quarters
Answer:

Step-by-step explanation:
Let's find a solution by understanding the following:
The acceleration rate is defined as the change of velocity within a time interval, which can be written as:
where:
A=acceleration rate
Vf=final velocity
Vi=initial velocity
T=time required for passing from Vi to Vf.
Using the problem's data we have:
Vf=65miles/hour
Vi=6miles/hour
T=14.8seconds
Using the acceleration rate equation we have:
, but look that velocities use 'hours' unit while 'T' uses 'seconds'.
So we need to transform 14.8seconds into Xhours, as follows:


Using X=0.0041hours in the previous equation instead of 14.8seconds we have:





In conclusion, the acceleration rate is 
Answer:
5x + 3
Step-by-step explanation:
1) Collect like terms.
(2x − x + 3x + x) + (5 − 2)
2) Simplify
5 x + 3
A transversal is a line that intersects two or more other lines. When it intersects parallel lines, many angles are congruent. Parallel lines<span> are two </span>lines<span> that are always the same distance apart and never touch.</span>
Answer:
C) A histogram because the class organizes the data into different ranges or intervals.
Step-by-step explanation:
A histogram is a graphical representation of numerical data. It is an approximate approach that groups a set of data into ranges on the x axis and having their match frequencies on the y axis.
A histogram makes it possible to represent a large amount of data and frequency in just one graph because of the interval/range option.
Because Mariner Middle school has a large number of students (550) and their height organized into equal intervals, the histogram is the best option.