The equation for this would be 41/4 + 52/3 - 41/3= ?
So then you just change all the denominators to their lcm, which is 12 and multiply the numerator accordingly.
123/12 + 208/12 - 164/12 = 167/12
Answer:
The expected number of minutes the rat will be trapped in the maze is 21 minutes.
Step-by-step explanation:
The rat has two directions to leave the maze.
The probability of selecting any of the two directions is, 
.
If the rat selects the right direction, the rat will return to the starting point after 3 minutes.
If the rat selects the left direction then the rat will leave the maze with probability 
after 2 minutes. And with probability 
the rat will return to the starting point after 5 minutes of wandering.
Let <em>X</em> = number of minutes the rat will be trapped in the maze.
Compute the expected value of <em>X</em> as follows:
![E(X)=[(3+E(X)\times\frac{1}{2} ]+[2\times\frac{1}{6} ]+[(5+E(X)\times\frac{2}{6} ]\\E(X)=\frac{3}{2} +\frac{E(X)}{2}+\frac{1}{3}+\frac{5}{3} +\frac{E(X)}{3} \\E(X)-\frac{E(X)}{2}-\frac{E(X)}{3}=\frac{3}{2} +\frac{1}{3}+\frac{5}{3} \\\frac{6E(X)-3E(X)-2E(X)}{6}=\frac{9+2+10}{6}\\\frac{E(X)}{6}=\frac{21}{6}\\E(X)=21](https://tex.z-dn.net/?f=E%28X%29%3D%5B%283%2BE%28X%29%5Ctimes%5Cfrac%7B1%7D%7B2%7D%20%5D%2B%5B2%5Ctimes%5Cfrac%7B1%7D%7B6%7D%20%5D%2B%5B%285%2BE%28X%29%5Ctimes%5Cfrac%7B2%7D%7B6%7D%20%5D%5C%5CE%28X%29%3D%5Cfrac%7B3%7D%7B2%7D%20%2B%5Cfrac%7BE%28X%29%7D%7B2%7D%2B%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B5%7D%7B3%7D%20%2B%5Cfrac%7BE%28X%29%7D%7B3%7D%20%5C%5CE%28X%29-%5Cfrac%7BE%28X%29%7D%7B2%7D-%5Cfrac%7BE%28X%29%7D%7B3%7D%3D%5Cfrac%7B3%7D%7B2%7D%20%2B%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B5%7D%7B3%7D%20%5C%5C%5Cfrac%7B6E%28X%29-3E%28X%29-2E%28X%29%7D%7B6%7D%3D%5Cfrac%7B9%2B2%2B10%7D%7B6%7D%5C%5C%5Cfrac%7BE%28X%29%7D%7B6%7D%3D%5Cfrac%7B21%7D%7B6%7D%5C%5CE%28X%29%3D21)
Thus, the expected number of minutes the rat will be trapped in the maze is 21 minutes.
3.482×10^9
Imagine the decimal at the end of the last 0 and move it 9 places to the left
Since the girl scout sold 5 more boxes on the second week, we have (x + 5) number of boxes sold for the second week. Now, for the third week, since it's double that of the second week, we have 2(x + 5). Thus, we have the following:
first week: x
second week: x + 5
third week: 2(x + 5)
Given that the total number of boxes sold for the three weeks is 431. We have
x + (x + 5) + 2(x + 5) = 431
x + x + 5 + 2x + 10 = 431
4x + 15 = 431
4x = 431 - 15
4x = 416
x = 104
We have now the value of x. Using this, we can find the values for the second and third week.
x + 5 = `104 + 5 = 109
2(x + 5) = 2(109) = 218
Answer:
first week: 104
second week: 109
third week: 218
Answer:
x=12
Step-by-step explanation:
opposite sides of a parallelogram are congruent, if that is a parallelogram
