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3 years ago

4/9÷1 7/15

Mathematics

1 answer:

guajiro [1.7K]3 years ago

6 0

9514 1404 393

Answer:

10/33

Step-by-step explanation:

The usual approach (if your calculator won't do this for you) is to convert the mixed number to an improper fraction, then perform the division. That division can be accomplished by multiplying the numerator by the inverse of the denominator.

1 7/15 = (15+7)/15 = 22/15

Then ...

(4/9)/(22/15) = (4/9)(15/22) = (2·2·3·5)/(3·3·2·11) = (2·5)/(3·11) = 10/33

_____

<em>Alternate solution</em>

Both fractions can be given the same denominator:

4/9 = 20/45

1 7/15 = 22/15 = 66/45

Now, the division is ...

(20/45)/(66/45) = 20/66 = 10/33

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Help ASP. what 3/4 divided by 1/8

iris [78.8K]

Answer:

Step-by-step explanation:

3/4 / 1/8

3/4 x 8/1

24/4

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME!!!! WILL REWARD BRAINLIEST!!!!!

Sergeu [11.5K]

Answer:

-4 and -2.

Step-by-step explanation:

First of all,... OH MAN,... that is serious brain twisting logic (if you can call it logic) and to be fair I had to ask a math expert person I'm acquainted with,... cause I didn't know either,... so nothing to be ashamed about,...

If we let 2x equal the lesser of the two consecutive EVEN integers, and we let y equal 2x+2 be the greater of the two consecutive EVEN integers,

(For example, this is like x = 1, so 2x=2, y=4 or x=7, so 2x=14 and y=16, we add 2 to the lesser even integer to get the next CONSECUTIVE even integer.)

This, y=2x+2, is one of the equations we need. To get the other,

"Four times the lesser (4*2x) is (=) 12 less (-12) than twice the greater (2y)."

Doing it all in math, we get:

4(2x) = 2y - 12

This simplifies to:

8x = 2y - 12

And using the first equation (y=2x+2) we can substitute "2x+2" in for "y"

8x = 2(2x + 2) - 12

Simplify the right side by first distributing:

8x = 4x + 4 - 12

Combine like terms on the right.

8x = 4x - 8

Subtract 4x from both sides

4x = -8

Divide both sides by 4

x= -2

Remember, our lesser even integer is 2x, so the lesser integer is 2*(-2)= -4, the greater is (-4)+2= -2.

Final answer: The two consecutive even integers are -4 and -2.

To be even more fair I don't fully understand this completely either,... he explained it to me and I and <em>getting</em> it,... so anyway,... Hope it helps, and

Chow,...!

5 0

3 years ago

eight cards are drawn from a standard deck of 52 cards. how many hands off with cards contain exactly three queens and three jac

d1i1m1o1n [39]

Answer:

15,136 hands off with cards contain exactly three queens and three jacks.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Standard deck:

4 queens and 4 jacks.

The other 52 - 8 = 44 cards are neither queens nor jacks.

Wow many hands off with cards contain exactly three queens and three jacks?

3 queens from a set of 4.

3 jacks from a set of 4.

2 other cards(not queens neither jacks) from the other 44. So

$C_{4,3}C_{4,3}C_{44,2} = \frac{4!}{1!3!} \times \frac{4!}{1!3!} \frac{44!}{2!42!} = 4*4*22*43 = 15136$

15,136 hands off with cards contain exactly three queens and three jacks.

4 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST!!!!!

Zolol [24]

B is the correct answer. I hope this helps!

8 0

4 years ago

Read 2 more answers

Brandi jogged 2 1\2 miles in 30 minutes. Sharma jogged 3 1\2 miles in 3\4 hour. who jogged at slower rate

Mrrafil [7]

Answer:

The speed of Sharma is slower than the speed of Brandi

I.e ∵ 4.67 miles per hour 5 miles per hour

∴ $S_2$ $S_1$

Step-by-step explanation:

Given as :

The distance cover by Brandi = $D_1$ = 2 $\frac{1}{2}$ = $\frac{5}{2}$

The Time taken by Brandi for jogging = $T_1$ = 30 minutes = $\frac{1}{2}$ hour

Let the speed of Brandi = $S_1$ = $\dfrac{\textrm Distance }{\textrm Time}$

or, $S_1$ = $\dfrac{\textrm [tex]D_1$ }{\textrm $T_1$ }[/tex]

Or. $S_1$ = $\frac{\frac{5}{2}}{\frac{1}{2}}$

∴ $S_1$ = 5 miles per hour

Again

The distance cover by Sharma = $D_2$ = 3 $\frac{1}{2}$ = $\frac{7}{2}$

The Time taken by Sharma for jogging = $T_2$ = $\frac{3}{4}$ hour

Let the speed of Sharma = $S_2$ = $\dfrac{\textrm Distance }{\textrm Time}$

or, $S_2$ = $\dfrac{\textrm [tex]D_2$ }{\textrm $T_2$ }[/tex]

Or. $S_2$ = $\frac{\frac{7}{2}}{\frac{3}{4}}$

∴ $S_2$ = $\frac{14}{3}$ = 4.67 miles per hour

Now, ∵ 4.67 miles per hour 5 miles per hour

∴ $S_2$ $S_1$

So, Sharma jogged at slower late

Hence The speed of Sharma is slower than the speed of Brandi Answer

3 0

4 years ago