<span>x = 4*3^(3/8) - 2
...............................</span>
12/X=X/6
X^2=72
X= 8.48
X=8.5
18/y=y/12
Y-^2= 216
Y= 14.69
Y= 14.7
Answer:
There are 220 ways by which the medals can be awarded to three of the 15 gymnast, if exactly one of the Americans wins a medal
Step-by-step explanation:
From the question, we have;
The number of gymnast in the Olympic women's competition = 15
The number of the gymnast who are Americans = 4
The number of medals awarded = 3 medals
The number of ways hat the medals can be awarded to the three of the gymnast if exactly one of the Americans wins a medal is given as follows;
The number of ways one of the medals can be won by one of the four Americans = ₄C₁ = 4 ways
The number of ways the other two medals can be won by the remaining 11 gymnast = ₁₁C₂ = 55 ways
Therefore, the total number of ways, 'N', the medals can be awarded to three of the 15 gymnast, if exactly one of the Americans wins a medal is given as follows;
N = ₄C₁ × ₁₁C₂
∴ N = 4 × 55 = 220
Answer:
13
Step-by-step explanation:
Number of students that attended more than play = percentage of students that attended more than play x total number of students
5.5% x 232
0.055 x 232 = 12.76 students
to round off to the nearest whole number, look at the first number after the decimal, if it is less than 5, add zero to the units term, If it is equal or greater than 5, add 1 to the units term.
Since the first term is 7 which is greater than 5, 1 would be added to it.
This gives 13
