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2 years ago

23. Daniel bought a gallons of paint at the store for a project. At the end of his project,

Mathematics

1 answer:

Anna [14]2 years ago

4 0

Answer:

Based on your responses and my understanding from what you have said the answer is B.

Step-by-step explanation:

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Mary’s yard is a mess. She needs to hire someone to prune her trees and shrubs. A landscaping service she calls quotes her a pri

UNO [17]

Answer:

I think it's C

Step-by-step explanation:

Maey should hire a landscaping service and if ther is more than 7.5h she could hire her neighbour

4 0

2 years ago

Read 2 more answers

The measure of an angle that is its own supplement is

kipiarov [429]

Answer: 90 degrees

============================

Explanation:

Let x and y be the two angles. Because they are supplementary angles, this means x+y = 180. Also since we're told that the angle is its own supplement, we can say that y = x.

Consequently, we can replace y with x and solve for x like so:

x+y = 180

x+x = 180 .... y is replaced with x since y = x

2x = 180

2x/2 = 180/2

x = 90

This means y = 90 as well. As a check, note how

x+y = 90+90 = 180

which verifies our answer.

7 0

3 years ago

Read 2 more answers

Linear equation of line with slope 1/4

MrRa [10]

Answer:

1/4x

Step-by-step explanation:

1/4x is a linear equation because it has a constant slope, and the slope of a line is shown before the x.

4 0

3 years ago

Need help regarding radioactive decay type of question

Alik [6]

By applying the radioactive simple decay model, we find that the initial quantity of the radioactive isotope is equal to approximately 5.63 grams.

<h3>How to determine the initial mass of a radioactive isotope</h3>

Mass of radioactive isotopes (m (t)), in grams, decay exponentially in time according to the following model:

$m(t) = m_{o}\cdot e^{-t/\tau}$ (1)

Where:

$m_{o}$ - Initial mass, in grams
t - Time, in years
τ - Time constant, in years

The time constant can be found in terms of half-life:

τ = t'/㏑ 2

If we know that t' = 24100 yr, t = 1000 yr and m(t) = 5.4 g, then the initial mass of the radioactive isotope is:

τ = 24100 yr/㏑ 2

τ ≈ 34768.95 yr

$5.4 = m_{o}\cdot e^{-1000/24100}$

$m_{o} = 5.629\,g$

By applying the radioactive simple decay model, we find that the initial quantity of the radioactive isotope is equal to approximately 5.63 grams.

To learn more on radioactive decay: brainly.com/question/1770619

#SPJ1

8 0

2 years ago

Afreen says, "I am thinking of 3 consecutive numbers. The first is a multiple of 4, the second is a multiple of 5 and the third

IgorLugansk [536]

Answer:

The 3 ses that we found are:

{4, 5, 6}

{64, 65, 66}

{124, 125, 126}

Step-by-step explanation:

3 consecutive numbers are written as:

n, (n + 1), (n + 2)

We know that the first one is a multiple of 4.

Then n is a multiple of 4:

n = k*4

where k is an integer.

The second one is a multiple of 5, then:

(n + 1) = j*5

where j is an integer.

The last one is a multiple of 6.

(n + 2) = p*6

where p is an integer.

We want to find 3 sets.

The first one is trivial:

n = 4

n + 1 = 5

n + 2 = 6

4 is a multiple of 4

5 is a multiple of 5

6 is a multiple of 6.

Now let's find a set that is not trivial.

First, remember that all the multiples of 5 end with a 0 or a 5,

Then we can look for a value n, that is multiple of 4, and that has a last units digit equal to 4 (then the next one will have a units digit and will be multiple of 5)

For example, 4*6 = 24

24 is a multiple of 4.

The next number is 24 + 1 = 25, which is multiple of 5.

The next number is 25 + 1 = 26, which is not multiple of 6.

So let's try again.

4*11 = 44, is a multiple of 4.

The next number is 44 + 1 = 45

45 is a multiple of 5.

The next number is 45 + 1 = 46, which is not multiple of 6

So we need to try with another set.

4*16 = 64, is a multiple of 4.

The next number is 64 + 1 = 65, which is multiple of 5.

The next number is 66, which is multiple of 6:

6*11 = 66

Then the set:

n = 64

n + 1 = 65

n + 2 = 66

Is a possible set.

Now we can keep trying this, we can see that the next set has the numbers:

n = 4*31 = 124 is a multiple of 4.

The next number, is 124 + 1 = 125, which is a multiple of 5.

The next number is 125 + 1 = 126, which is multiple of 6

6*21 = 126

Then the set:

n = 124

n + 1 = 125

n + 2 = 126

Is another possible set.

The 3 ses that we found are:

{4, 5, 6}

{64, 65, 66}

{124, 125, 126}

7 0

3 years ago