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joja [24]
2 years ago
5

23. Daniel bought a gallons of paint at the store for a project. At the end of his project,

Mathematics
1 answer:
Anna [14]2 years ago
4 0

Answer:

Based on your responses and my understanding from what you have said the answer is B.

Step-by-step explanation:

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2000 is 1000 times larger than 2
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7/8 - 1/4 - 1/2= ??
madreJ [45]

Step-by-step explanation:

We can break this up into pieces, first we do, 7/8 - 1/4, find the least common denominator which is 8, so the equation will be 7/8 - 2/8, which we can now subtract and will give us, 5/8, now that we have done that, we can do 5/8 - 1/2. Since we know that half of 8 (our denominator) is 4. Then the equation would be 5/8 - 4/8, which brings us to 1/8 as our final answer.

Cheers!

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2 years ago
I need help so yea please help
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Answer:

option 3

Step-by-step explanation:

divide the diameter by 2 to get the radius.

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2 years ago
2 tens plus 13 ones
Anton [14]

Hello from MrBillDoesMath!

Answer:

33

Discussion:

2 tens = 2 * 10 = 20

13 ones = 13 * 1  13

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3 0
3 years ago
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Suppose that the weights of passengers on a flight to Greenland on Frigid Aire Lines are normal with mean 175 pounds and standar
Natali5045456 [20]

Answer:

The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 175, \sigma = 22

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?

90th percentile

The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 175}{22}

X - 175 = 22*1.28

X = 203.16

The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds

6 0
3 years ago
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