2000 is 1000 times larger than 2
Step-by-step explanation:
We can break this up into pieces, first we do, 7/8 - 1/4, find the least common denominator which is 8, so the equation will be 7/8 - 2/8, which we can now subtract and will give us, 5/8, now that we have done that, we can do 5/8 - 1/2. Since we know that half of 8 (our denominator) is 4. Then the equation would be 5/8 - 4/8, which brings us to 1/8 as our final answer.
Cheers!
Answer:
option 3
Step-by-step explanation:
divide the diameter by 2 to get the radius.
pi×r^2
3.14×42^2=5538.96 km^2
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Answer:
33
Discussion:
2 tens = 2 * 10 = 20
13 ones = 13 * 1 13
=> 2 tens + 13 ones = 20 + 13 = 33
Thank you,
MrB
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So




The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds