Answer:
A, B and E could not be probabilities
Step-by-step explanation:
By definition, <u>a probability could be any number between 0 and 1. </u>So a probability P would be 0≤P≤1. In percentages, 0% ≤ P ≤ 100%
Considering this we would have that:
A) 110% could not be a probability because it's larger than 100%
B) 5.42 could not be a probability because it's larger than 1.
C) 0.001 could be a probability because it's larger than 0 and smaller than 1 (It doesn't matter how small it is)
D) 0.58 could be a probability because it's between 0 and 1.
E) -120% could not be a probability because it's smaller than zero. (it's a negative number)
Thus, A), B) and E) could not be probabilities.
By multiplying the factors together you’ll get 6
Answer:
A
Step-by-step explanation:
The required answer but,i may be wrong.
Answer:
The expected value for the number of inspections until a defective unit is found 17.
Step-by-step explanation:
Percentage of defective microchips = 6%
Let the total number of inspection = x
number of defective microchip = 1
As we know
1/x = 6%
1/x = 0.06
x = 1/ 0.06
x = 16.67 inspections
x = 17 ( rounded off to nearest whole number )
17 inspection is done until the defective microchip is found.
