Answer:
Width = 26 inches
Step-by-step explanation:
The area of the rectangle is:
area = (length*width)
416 = a*b
a = b/2 + 3
a = length
b = width
then:
416 = (b/2 + 3) (b)
416 = b*b/2 + b*3
416 = b²/2 + 3b
0 = b²/2 + 3b - 416
b = {-(+3)±√((3²)-(4*1/2*-416))} / (2*1/2)
b = {-3±√(9+832)} / 1
b = {-3±√841}
b = -3±29
only take the positive value becuse is a natural number
b = -3+29
b = 26 inches
a = b/2 + 3
a = 26/2 + 3
a = 13 + 3
a = 16 inches
Check:
416 = 16 * 26
Answer:
8428
Step-by-step explanation:
According to the Question,
- Given, A theater has 56 rows of seats. If there are 13 seats in the first row, 18 in the 2nd row, 23 in the 3rd row.
We have a number sequence 13, 18, 23, ...
- We can say that this is an arithmetic sequence because of the common difference 'd', is equal to 5, and the first term 'a1' is equal to 13.
- The formula for the sum of an arithmetic sequence with n terms is given is
.
Substitute the given values into the equation to solve for the sum of the 56 rows of seats.
![S_56= \frac{56}{2}[2(13)+(56-1)(5)]\\S_{56}=28\left[26+275\right]\\S_{56}=28\left[301\right]\\S_{56}=8428](https://tex.z-dn.net/?f=S_56%3D%20%5Cfrac%7B56%7D%7B2%7D%5B2%2813%29%2B%2856-1%29%285%29%5D%5C%5CS_%7B56%7D%3D28%5Cleft%5B26%2B275%5Cright%5D%5C%5CS_%7B56%7D%3D28%5Cleft%5B301%5Cright%5D%5C%5CS_%7B56%7D%3D8428)
Therefore, there are 8428 seats in all.
If each of the 28 students made at least $25, you would multiply 28 and 25 together to obtain the least amount of money the class raised. That gets, 28x25 = 700. The class made at least $700.
Answer:
Cylinder A= 603.81
Cylinder B= 603.19
Cylinder A holds more sand than Cylinder B
Step-by-step explanation: