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Taya2010 [7]
3 years ago
6

Quadrilateral ABCD has vertices at

Mathematics
2 answers:
omeli [17]3 years ago
5 0
<h2>Question:</h2>

What word below best describes this quadrilateral?

<h2>Answer:</h2>

<u>B</u><u>.</u><u> </u><u>Parallelogram</u><u> </u>

<h3><u>#CARRYONLEARNING</u><u> </u></h3><h3><u>#STUDYWELL</u><u> </u></h3>
sweet [91]3 years ago
5 0
<h2>Question:</h2>

What word below best describes this quadrilateral?

<h2>Choosing:</h2>

A.) Rhombus

B.) Parallelogram

C.) Rectangle

D.) Square

<h2>Answer:</h2>

<u>B</u><u>.</u><u> </u><u>Parallelogram</u><u> </u>

<h3><u>#READINGHELPSWITHLEARNING</u><u> </u></h3><h3><u>#CARRYONLEARNING</u><u> </u></h3><h3><u>#STUDYWELL</u><u> </u></h3>
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KIM [24]

The correct answer is C.


You can tell this by factoring the equation to get the zeros. To start, pull out the greatest common factor.


f(x) = x^4 + x^3 - 2x^2


Since each term has at least x^2, we can factor it out.


f(x) = x^2(x^2 + x - 2)


Now we can factor the inside by looking for factors of the constant, which is 2, that add up to the coefficient of x. 2 and -1 both add up to 1 and multiply to -2. So, we place these two numbers in parenthesis with an x.


f(x) = x^2(x + 2)(x - 1)


Now we can also separate the x^2 into 2 x's.


f(x) = (x)(x)(x + 2)(x - 1)


To find the zeros, we need to set them all equal to 0


x = 0


x = 0


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Since there are two 0's, we know the graph just touches there. Since there are 1 of the other two numbers, we know that it crosses there.

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