Answer:
y= 3x^2 y= 3^x
1. 3. 3
2. 12. 9
Step-by-step explanation:
3(1)^1
3
3^1
3
3(2)^2
3(4)
12
3^2
9
here are the steps hope it helps
Sum of the numbers in the set: 42+37+32+29+20 =160
Current mean: 160/5 = 32
Median = the valvue of the middle = 32.
New mean: 32+10= 42.
Sum of numbers in the new set = 42*8 = 336
Difference: 336 - 160 = 176
I want to include 32, so that the new median stays in 32.
So the other two numbers must add 176 - 32 = 144
I will use a smaller number than 32 and the other greater (again in order to keep the same median.
I will choose 28 and 144 - 28 = 116.
So my three new numbers are 28, 32 and 116 and the new set is {116, 42, 37, 32, 32, 29,28, 20}
Checking:
Sum of the terms: 116+42+37+32+32+29+28+20 = 336
Mean = 336 / 8 = 42, which is 10 more than the original mean.
And the new median is (32+32)/2 = 32. The same of the original set.
Answer: i dunno what '.......' was suppose to mean but 11 + 15 + 19 + 83 = 128
Step-by-step explanation: b more specific dood -_-
Answer:
Step-by-step explanation:
The inverse of the function is the "opposite" of a function, so to speak. One can find it by treating it like a literal equation with 2 variables, one now has to solve for the other variable presnet. In other words, treat the therm (f(x)) like another variable in the equation. Now one has to solve for (x) in terms of (f(x)).
Manipulate the literal equation with inverse operations;
Now switch the variables;
The 
signifies that the written function is the inverse of the original function.
