Question

Solve the system algebraically.

Answer 1

Answer:

Let 2x + y - 10 = 0 be equation (a).

Let x - y - 5 = 0 be equation (b).

Make y the subject in equation (b):

${ \tt{x - y - 5 = 0}} \\ { \tt{y = x - 5}}$

Substitute for y in equation (a):

${ \tt{2x + (x - 5) - 10 = 0}} \\ { \tt{3x - 15 = 0}} \\ { \tt{3x = 15}} \\ { \tt{x = 5}}$

Find y in any equation of your choice:

${ \tt{y = (5) - 5}} \\ y = 0$

Answer 2

Hope this helps! I used substitution method! feel free to clarify!