Answer:
F=Fahrenheit and C=Celsius
Step-by-step explanation:
Recall that a rational function:
has a vertical asymptote at x₀ if and only if:
Also, the roots of the above rational function are the same as P(x).
Since the rational function has a vertical asymptote at x=-1, we get that its denominator must be:
Since the rational function has a double zero at x=2 we get that its numerator must be of the form:
Finally, since the rational function has y-intercept at (0,2) we get that:
Simplifying the above equation we get:
Dividing the above equation by 4 we get:
Therefore, the rational function that satisfies the given conditions is:
Answer:
The numerator is:
The denominator is:
The equation of the sinusoidal function is y = -2sin(x + 1.5) - 3
<h3>The sinusoidal function</h3>
The minimum and the maximum of the function are
The amplitude (A) is calculated as:
A = 0.5 * (Maximum - Minimum)
So, we have:
A = 0.5 * (-5 + 1)
A = -2
The vertical shift (d) is calculated as:
d = 0.5 * (Maximum + Minimum)
So, we have:
d = 0.5 * (-5 - 1)
d = -3
The period (P) is calculated as:
P = 2π/B
From the graph,
B = 1
So, we have:
P = 2π/1
P = 2π
So, the amplitude is -2 and the period is 2π.
<h3>The equation of the sine function</h3>
In (a), we have:
A = -2
B = 1
d = -3
A sine function is represented as:
y = A sin(Bx + C) + D
So, we have:
y = -2sin(x + C) - 3
The graph passes through the point (0, -5)
So, we have
-5 = -2sin(0 + C) - 3
Solve for C, we have
C = 1.5
So, we have:
y = -2sin(x + 1.5) - 3
Hence, the equation of the sinusoidal function is y = -2sin(x + 1.5) - 3
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An expression is defined as a set of numbers, variables, and mathematical operations. The second student is correct.
<h3>What is an Expression?</h3>
In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.
Given One student simplified x⁵ + x⁵ to x¹⁰. The second student simplified x⁵+x⁵ to 2x⁵. Since the simplification of (x⁵+x⁵) is equal to 2x⁵. Therefore, the second student is correct.
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