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NikAS [45]
3 years ago
5

The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?

Mathematics
2 answers:
artcher [175]3 years ago
8 0
Translating the question
x^2=10-7x
rearrange
x^2+7x-10=0
using quadratic formula
x=-7+ \sqrt{49+40}all over 2 0r  x=-7- \sqrt{49+40}all over 2
therefore x=1.2 or x=-1.2


Lena [83]3 years ago
4 0
X^2- 7x + 10 = 0 2 possible soultions are 5 or 2
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                                   2      2
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2x + 1y = 7     ⇒ 2x + 1y = 7
1x -  2y = -14 ⇒ <u>2x  - 4y  = -28</u>
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                             <u>      -7   -7</u>
                                   <u>2x</u> = <u>0</u>
                                    2     2
                                    x = 0
                              (x, y) = (0, 7)
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