Answer:
3-1 = 2 units is the distance between the points.
Answer:
a=1.5, b= 3
Step-by-step explanation:
sum of all sides will give us perimeter. Therefore
2a+b+6a+2b+1+4a=28
12a+3b+1=28
12a+3b=27....eqn1
since t two sides of this isosceles triangle are equal:
2a+b=4a
2a=b

substituting 
in the first equation whenever we encounter a we will have:

6b+3b=27
9b=27
b=3
therefore 
So to get the answer you do 100100100+303030-101010 which = 100302120 x 10 (the amount she/he gets for each subscriber) which is the amount of money Kiersten earned.
Hope this helped
Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
krok68 [10]
Answer:
Mean = 51.4.
Mode = 49.
Median = 52.
Range = 6.
Step-by-step explanation:
Mean = Sum of all observations / Number of observations.
Mean = (49+49+54+55+52+49+52)/7
Mean = 360/7
Mean = 51.4 (to the nearest tenth).
Mode = The most repeated values = 49 (repeated 3 times).
Range = Largest Value - Smallest Value = 55 - 49 = 6.
Median = The central value of the data.
First, arrange the data in the ascending order: 49, 49, 49, 52, 54, 55, 55.
It can be seen that the middle value is 52. Therefore, median = 52!!!
The true average strain in a way that conveys information about precision and reliability is 27.314.
Given that sample size is 20, mean is 26%, standard deviation is 3.4, confidence level is 95%.
We have to calculate the true average strain in a way that conveys information about precision and reliability.
We have to use t test in our problem because sample size is less than 30.
Weknow that,
t=x bar-μ/s
where μ is sample mean,
s is sample standard deviation.
Degree of freedom=n-1
=20-1
=19
T value at 95% confidence interval=1.7281
put the values in the formula of t given above.
1.7291=x bar-26/3.4/
1.7291=xbar-26/3.4/4.47
1.7291= x bar-26/0.76
1.7291*0.76=x bar-26
1.314=x bar-26
x bar=26+1.314
x bar=27.314
After rounding it will be 27.31
Hence the true average strain in a way that conveys information about precision and reliability is 27.31%.
Learn more about t test at brainly.com/question/6589776
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