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Volgvan
3 years ago
15

What are the x- and y-intercepts of −6x+4y=96 ?

Mathematics
1 answer:
ankoles [38]3 years ago
3 0
* intercepts "x" --> y=0

-6x  + 4(0) = 96
-6x = 96
x = - \frac{96}{6}

x = 16  

(16,0)

*intercepts "y" --> x=0

-6(0) + 4y = 96
4y = 96
y = \frac{96}{4}

y = 24

(0,24)
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