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WINSTONCH [101]
3 years ago
9

One number is 9 more than another. if the sum of the two numbers is 171, find the two numbers

Mathematics
1 answer:
allochka39001 [22]3 years ago
4 0
Let x be the 1st number
x + 9 be the second number

Equation:
x + x+9 = 171

Solution:
2x + 9 = 171
2x = 171 - 9
2x = 162
x = 81
x + 9 = 90

81 + 90 = 171
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Answer:

y = 3(2)^{x}

Step-by-step explanation:

Substitute the given points into the function and solve for a and b

Using (2, 12)

12 = ab² → (1)

Using (5, 96)

96 = ab^{5} → (2)

Divide (2) by (1)

\frac{ab^5}{ab^2} = \frac{96}{12} , that is

b³ = 8 ( take the cube root of both sides )

b = \sqrt[3]{8} = 2

Substitute b = 2 into (1) and solve for a

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Thus

y = 3(2)^{x} ← is the exponential function

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What are the factors of 2a³ + a² + 2a + 1?
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There are 200 student in middle school and three fifths of them are girls how many are boys?
nadezda [96]

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A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.
dimulka [17.4K]

Answer:

a. 39.55%

b. 44.02%

Step-by-step explanation:

We have the following data:

n = 5

x = 1

p = 5/20 = 0.25

to. If the sampling is done with replacement.

We apply the binomial distribution formula, which is as follows:

P = nCx * (p ^ x) * ((1-p) ^ (n-x))

Where nCx, is a combination, and is equal to:

nCx = n! / x! * (n-x)!

replacing we have:

5C1 = 5! / 1! * 4! = 5

replacing in the main formula:

P = 5 * (0.25 ^ 1) * ((1- 0.25) ^ (5-1))

P = 0.3955

that is, without replacing the probability is 39.55%

b. if the sampling is done without replacement.

Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

5C1 = 5! / 1! * 4! = 5

the second is when n = 20 and x = 5, this is all possible scenarios.

20C5 = 20! / 5! * 15! = 15504

and the third is when n = 15 (20-5) and x = 4 (5-1), which corresponds to the cases when none were damaged

15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

P = (5C1 * 15C4) / 20C5

Replacing:

P = 5 * 1365/15504

P = 0.4402

Which means that without replacing the probability is 44.02%

7 0
3 years ago
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