Answer:
The angle between the given vectors u and v is ![\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]](https://tex.z-dn.net/?f=%5Ctheta%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B3%7D%7B%5Csqrt%7B10%7D%7D%5Cright%5D)
Step-by-step explanation:
Given vectors are
and 
Now compute the dot product of u and v:




Now find the magnitude of u and v:









To find the angle between the given vectors

![\theta=cos^{-1}\left[\frac{\overrightarrow{u}.\overrightarrow{v}}{|\overrightarrow{u}|\overrightarrow{v}|}\right]](https://tex.z-dn.net/?f=%5Ctheta%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B%5Coverrightarrow%7Bu%7D.%5Coverrightarrow%7Bv%7D%7D%7B%7C%5Coverrightarrow%7Bu%7D%7C%5Coverrightarrow%7Bv%7D%7C%7D%5Cright%5D)
![=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]](https://tex.z-dn.net/?f=%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B15%7D%7B5%5Ctimes%20%5Csqrt%7B10%7D%7D%5Cright%5D)
![=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]](https://tex.z-dn.net/?f=%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B15%7D%7B5%5Ctimes%20%5Csqrt%7B10%7D%7D%5Cright%5D)
![\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]](https://tex.z-dn.net/?f=%5Ctheta%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B3%7D%7B%5Csqrt%7B10%7D%7D%5Cright%5D)
Therefore the angle between the vectors u and v is
![\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]](https://tex.z-dn.net/?f=%5Ctheta%3Dcos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B3%7D%7B%5Csqrt%7B10%7D%7D%5Cright%5D)
Y = 0.08x2-1.6x+13 and y = 0.08(x-10)2<span>+5 is the correct answer :)</span>
The answer is: 2 + (6 * y)
Why?
It's asking for 2 more than, which is generally 2 +, the product, which signifies multiplication, of 6 and y, the numbers that are being multiplied.
Put all those terms together, you end up getting 2 + (6 * y).
The answer for the first question would be 3952+3952 =7903
Answer:
Width of the box = 2 inches
Step-by-step explanation:
Volume of a box = length × width × height
Volume of the box = 240 cubic inches
Length of the box = (x + 8) inches
Width of the box = x inches
Height of the box = 12 inches
Volume of a box = length × width × height
240 = (x + 8) * x * 12
240 = (x² + 8x) * 12
240 = 12x² + 96x
12x² + 96x - 240 = 0
x² + 8x - 20 = 0
Solve quadratic equation using factorization method
x² + 10x - 2x - 20 = 0
x(x + 10) -2(x + 10) = 0
(x + 10) (x - 2) = 0
x + 10 = 0 OR x - 2 = 0
x = -10 OR x = 2
Width of the box can not be a negative value
Therefore,
Width of the box = 2 inches