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GrogVix [38]
3 years ago
13

I will mark Brainlyst

Mathematics
1 answer:
suter [353]3 years ago
8 0

Answer:

A because of its larger range

Step-by-step explanation:

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The equation of line L, is y = 5x + 1
Lynna [10]

Answer:

see explanation

Step-by-step explanation:

Parallel lines have equal slopes.

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 5x + 1 ← is in slope- intercept form

with slope m = 5

Rearrange 2y - 10x + 3 = 0 into this form

Add 10x to both sides

2y = 10x ( subtract 3 from both sides )

2y = 10x - 3 ( divide all terms by 2 )

y = 5x - \frac{3}{2} ← in slope- intercept form

with slope m = 5

Since both lines have a slope of 5 then they are parallel.

4 0
3 years ago
What is 312.15 in expanded form?
Andrei [34K]
300+10+2 +.10=.5 hope this helps you
3 0
3 years ago
What is the sum of 13+52 as the product of their GCF and another sum
vova2212 [387]
GCF(13; 52) = 13

13 = 13 · 1
52 = 13 · 4

13 + 52 = 13 · 1 + 13 ·4 = 13·(1 + 4)

Used distributive property: a(b + c) = ab + ac
4 0
3 years ago
Identify the number that does not belong with the other three. Explain your reasoning. negative 10 over 2, negative 13.4, square
11111nata11111 [884]
Sqrt 18 I believe :)
8 0
3 years ago
Read 2 more answers
The front of a storage bunker can be modeled by y=-5/216(x-72)(x+72), where x and y are measured in inches. The x axis represent
german
As far as I can make out this one.

the bunker is a 3D object, it has a height, with and length, however we're only concerned with the 2D front face, which has a length and width only.

we know the x-axis is the ground level, so the y-axis must be the scale for the length.

if we can find, using the provided model, the x-intercepts, namely where the x-axis gets touched, we can just get the distance between them and that's the ground level width.

keeping in mind that when the graph touches the x-axis, an x-intercept, "y" is 0.

\bf y=-\cfrac{5}{216}(x-72)(x+72)\implies \stackrel{y}{0}=-\cfrac{5}{216}(x-72)(x+72)
\\\\\\
0=\stackrel{\textit{difference of squares}}{(x-72)(x+72)}\implies 0=x^2-72^2\implies 72^2=x^2
\\\\\\
\pm\sqrt{72^2}=x\implies \pm 72=x

now, the distance from (-72, 0) and (72, 0) is just 72 +72, or 144.
3 0
3 years ago
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