Let x be the first digit.
Let y be the second digit.
Let z be the third digit.
x+y+z=18
y= (-2)(-4)
y= 8
x= 3^2
x= 9
Therefore z=1.
The number is
= 100x+10y+z
= 100(9)+10(8)+(1)
= 981
Answer:
the probability that a sample of 4 bags will have a mean weight less than 9.8 pounds is 0.05
Step-by-step explanation:
Given the data in the question;
μ_x = 10 pound bags
standard deviation s_x = 0.24 pounds
sample size n = 4
The bag weights are normally distributed so;
p( x' less than 9.8 ) will be;
p( (x'-μ_x' / s_x') < (9.8-μ_x' / s_x') )
we know that;
μ_x' = μ_x = 10
and s_x' = s_x/√n = 0.24/√4
so; we substitute
p( z < ( (9.8 - 10) / (0.24/√4) )
p( z < -0.2 / 0.12 )
p( z < -1.67 )
{ From z-table }
⇒ p( z < -1.67 ) = 0.0475 ≈ 0.05
Therefore, the probability that a sample of 4 bags will have a mean weight less than 9.8 pounds is 0.05
General term of a geometric sequence is
a(n)=a(1)×r^(n-1)
a1=5
a2=5×6=30
a3=5×6²=180
a4=5×6³=1080
0.86/5-0.3*0.5= 2 answers
1. can be 11/500
2. it can be 0.022 but im positive it has to be 11/500
Answer:
1919=0+1+0+1=2
Step-by-step explanation:
