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Maksim231197 [3]
1 year ago
12

Given 3x^2+x-4/x-1 what are the domain and range

Mathematics
1 answer:
Katarina [22]1 year ago
6 0

Answer:

  • doman: x ≠ 1
  • range: y ≠ 7

Step-by-step explanation:

The domain is the horizontal extent of the graph, the set of x-values for which the function is defined. The range is the vertical extent of the graph, the set of y-values defined by the function.

<h3>Simplified</h3>

The given function is undefined where its denominator is zero, at x=1. Everywhere else, it can be simplified to ...

  \dfrac{3x^2+x-4}{x-1}=\dfrac{(x-1)(3x+4)}{(x-1)}=3x+4\quad x\ne 1

<h3>Domain</h3>

The simplified function (3x+4) is defined for all values of x except x=1. The simplest description is ...

  x ≠ 1

In interval notation, this is ...

  (-∞, 1) ∪ (1, ∞)

<h3>Range</h3>

The simplified function is capable of producing all values of y except the one corresponding to x=1: 3(1)+4 = 7. The simplest description is ...

  y ≠ 7

In interval notation, this is ...

  (-∞, 7) ∪ (7, ∞)

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Solve the system x+3=22 2x-y=2
steposvetlana [31]

Hello from MrBillDoesMath!

Answer:

x = 19, y = 36

Discussion:

x + 3 = 22     (*)

2x - y = 2      (**)


Subtract 3 from both sides of (*)

x + 3 -3 = 22 = 3 = 19  =>

x = 19


Substitute x= 19 in (**)

2(19) - y = 2 =>

38 - y = 2 =>           (add y to both sides)

38 -y + y = 2 + y =>

38 = 2 + y  =>         (subtract 2 from both sides)

38 -2 = 2 -2 + y =>

36 = y


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


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