Given 3x^2+x-4/x-1 what are the domain and range
1 answer:
Answer:
- doman: x ≠ 1
- range: y ≠ 7
Step-by-step explanation:
The domain is the horizontal extent of the graph, the set of x-values for which the function is defined. The range is the vertical extent of the graph, the set of y-values defined by the function.
<h3>Simplified</h3>The given function is undefined where its denominator is zero, at x=1. Everywhere else, it can be simplified to ...
The simplified function (3x+4) is defined for all values of x except x=1. The simplest description is ...
x ≠ 1
In interval notation, this is ...
(-∞, 1) ∪ (1, ∞)
<h3>Range</h3>
The simplified function is capable of producing all values of y except the one corresponding to x=1: 3(1)+4 = 7. The simplest description is ...
y ≠ 7
In interval notation, this is ...
(-∞, 7) ∪ (7, ∞)
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Answer:
0.1190
Step-by-step explanation:
If z = -1.18, the total area to the left under the standard normal curve is taken from the z-distribution table attached;
P(z < - 1.18) = 0.1190
Also, to the right of z = 1.18, we have;
P(z > 1.18) = 1 - P(z < 1.18)
From the second image attached from z-table, we have;
P(z > 1.18) = 1 - 0.8810
P(z > 1.18) = 0.1190
Thus, the total area to the left of z= - 1.18 and to the right of z= 1.18 under the standard normal curve is 0.1190
