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1 year ago

Given 3x^2+x-4/x-1 what are the domain and range

Mathematics

1 answer:

Katarina [22]1 year ago

6 0

Answer:

doman: x ≠ 1
range: y ≠ 7

Step-by-step explanation:

The domain is the horizontal extent of the graph, the set of x-values for which the function is defined. The range is the vertical extent of the graph, the set of y-values defined by the function.

<h3>Simplified</h3>

The given function is undefined where its denominator is zero, at x=1. Everywhere else, it can be simplified to ...

$\dfrac{3x^2+x-4}{x-1}=\dfrac{(x-1)(3x+4)}{(x-1)}=3x+4\quad x\ne 1$

<h3>Domain</h3>

The simplified function (3x+4) is defined for all values of x except x=1. The simplest description is ...

x ≠ 1

In interval notation, this is ...

(-∞, 1) ∪ (1, ∞)

<h3>Range</h3>

The simplified function is capable of producing all values of y except the one corresponding to x=1: 3(1)+4 = 7. The simplest description is ...

y ≠ 7

In interval notation, this is ...

(-∞, 7) ∪ (7, ∞)

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Step-by-step explanation:

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2 years ago

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Makovka662 [10]

Answer:

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:Subtraction property of equality

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<u>:Substitution property of equality</u>

3. If 2x3 = 11, then 11 = 2x - 3.

<u>:Symmetric property of equality</u>

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Anuta_ua [19.1K]

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So for example:

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Step-by-step explanation:

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