The distance between each base on a baseball diamond is 70 feet. How far would a player have to throw the ball to get it from 1s
1 answer:
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Answer:
x = - 1, x =
Step-by-step explanation:
Given
8x² + 7x - 1 = 0 ← in standard form
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 8 × - 1 = - 8 and sum = + 7
The factors are + 8 and - 1
Use these factors to split the x- term
8x² + 8x - x - 1 = 0 ( factor the first/second and third/fourth terms )
8x(x + 1) - 1(x + 1) = 0 ← factor out (x + 1) from each term
(x + 1)(8x - 1) = 0
Equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
8x - 1 = 0 ⇒ 8x = 1 ⇒ x =
Answer:
Approximately 59 stacked cups.
Step-by-step explanation:
Given,
Height of a cup = 12.5 cm,
Two stacked cups = 14 cm,
Three stacked cups = 15.5 cm,
........, so on,....
Thus, there is an AP that represents the given situation,
12.5, 14, 15.5,....
First term is, a = 12.5,
Common difference, d = 1.5 cm,
Thus, the height of x cups is,
According to the question,
h(x) = 200
⇒ 1.5x + 11 = 200
⇒ 1.5x = 189
⇒ x = 59.3333333333 ≈ 59,
Hence, approximately 59 stacked cups will need.