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lara31 [8.8K]
3 years ago
6

A teacher brought some apples to distribute among students. After distributing 19 pounds of apples, 3 pounds of apples were left

. How many pounds of apples did the teacher originally bring? A. 3 B. 9 C. 16 D. 22
Mathematics
2 answers:
ozzi3 years ago
5 0

Answer:

19 pounds of apple was shared and 3 pounds of apple were left to be shared for the students

A

natta225 [31]3 years ago
4 0

Answer:

D. 22

Step-by-step explanation:

We're looking for the sum of 19 pounds and 3 pounds. The teacher gave out 19 pounds of apples. After giving them out, they had 3 pounds left of the total. To find the total, we need to add those amounts:

19 + 3 = 22

We can check our answer by doing this:

22 - 19 = 3

As you can see, if you had 22 pounds of apples and gave out 19 pounds, you are left with 3 pounds. This is the amount left, as mentioned in the problem. The answer is D.

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Two cards are drawn without replacement from a standard deck of 52 cards. What is the probability that one of the cards is red a
alukav5142 [94]
Total cards = 52
Total red cards = 26
Total black cards = 26

P(one red and one black) = P(red and then black)+ P(black and then red)
P(one red and one black) =(26/52)(26/51) + (26/52)(26/51)
P(one red and one black) = 26/51 (Answer A) 

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Answer: 26/51 (Answer A) 
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Solve for j: j + j / 2 + J + 5 = 45
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Answer:

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It would be the first answer.

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4 0
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Does anyone know the answer to this!?
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Answer:

|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

Step-by-step explanation:

You can use these Cramer's formulas to solve for x and y:

x=\dfrac{|A_x|}{|A|},\\ \\y=\dfrac{|A_y|}{|A|},

where

|A|=\left|\begin{array}{cc}12&-13\\ \\17&-22\end{array}\right|\\ \\ \\|A_x|=\left|\begin{array}{cc}7&-13\\ \\-51&-22\end{array}\right|\\ \\ \\|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

So,

|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|

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3 years ago
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