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Rus_ich [418]
3 years ago
12

Without calculating . How do you know |4x-7| =-1 has no solution

Mathematics
1 answer:
viktelen [127]3 years ago
7 0
Because the left side of the equation is an absolute value, making it impossible to = to -1.
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Which equation is correctly solved for y​
Radda [10]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
F(x) = a(x - h)power of 3 + k   please describe what a, h and k do within our function. 
Zarrin [17]

F(x) = a(x - h)³ + k

The parent graph is F(x) = x³

k - shifts the parent graph up k-units (or down if it is negative).  This is also called a vertical shift.

h - shifts the parent graph to the right h-units (or left if it is negative).  This is also called a horizontal shift.

a - stretches the parent graph vertically by a factor of "a"

Additonally, the coordinate (h, k) is the center/vertex of the graph.


6 0
3 years ago
Select the equation of a straight line that is parallel to the line 4y = 3x + 5
insens350 [35]

Answer:

One equation can be y = 3/4X +2

Step-by-step explanation:

Any equation that has a slope of 3/4 will be parallel to the line 4Y = 3X + 5 because the slope is the same. This can also be shown visually using any graphing calculator.

8 0
3 years ago
2×3 squared<br><img src="https://tex.z-dn.net/?f=2%20%5Ctimes%203%20%7B%3F%7D%5E%7B2%7D%20" id="TexFormula1" title="2 \times 3 {
morpeh [17]
2 x 3^2
2 x 9
18

18 is the answer
3 0
2 years ago
Read 2 more answers
The average performance rating of the employees at Company A is 6.5 on a scale from 1 to 10 (10 being highest). The standard dev
djyliett [7]

Answer:

The best choice would be hiring a random employee from company A

Step-by-step explanation:

<em>Supposing that the performance rating of employees follow approximately a normal distribution on both companies</em>, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.

In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings

The z-value corresponding to company A is

z=\frac{\bar x-\mu}{s}

where

\bar x = mean of company A

\mu = 5.5 (average of rating between 1 and 10)

s = standard deviation of company A

z=\frac{\bar x-\mu}{s}=\frac{6.5-5.5}{2.1}=0.7142

We do the same for company C

z=\frac{\bar x-\mu}{s}=\frac{7.4-5.5}{6.8}=0.2794

This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a  performance rating > 5.5.

So, the best choice would be hiring a random employee from company A

4 0
3 years ago
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