Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
To add any fraction You need to make sure that the denominator of the fractions are same. ( denominator in your sum is 19 )
10/19 + 3/19 ( we have the same denominator )
we can also write this problem like
( 10 + 3 ) / 19 { add the numerators together }
13 / 19
So correct option is B.
hope this helped.. :)
Answer:
x+7
Step-by-step explanation:
Remove Parentheses
Collect like terms
Calculate
<span> SO in total, Emily and Sarah had a total of 80
dollars in which Emily had twice as much as Sarah.
Let’s solve to find out how much their Money is.
=> Since the ratio of the given data is 2:1, 2 + 1 =3, so let’s divide 80 by
3
=> 80 / 3 = 26.667 ,
=> Emily has twice as this.
=> 26.667 * 2 = 53.33
=> Sarah has 26.67
Now, Sarah spent 1/3 of her money
=> 26.67 / 3 = 8.89 – her remaining money
Emily spent 17 dollars of her money
=> 53.33 – 17 = 36.33</span>
Answer:
The Subjects: The subject of this research are the drivers who were selected randomly to take part in the experiment
The Treatment: The treatment for this research will therefore be driving and also talking on a cell phone at the same time and also driving while not talking on the phone
The response variable for the experiment: The number of errors that will be made by the drivers as they drive on an obstacle course.
Step-by-step explanation:
