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garik1379 [7]
3 years ago
9

Simplify. (2x5+x3−3x4−x+8)−(7x5+2x4−12+6x−5x3+x2) Enter your answer, in standard form, in the box.

Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0

Answer:

-5 x^5 - 5 x^4 + 6 x^3 - x^2 - 7 x + 20

Step-by-step explanation:

(2x^5+x^3−3x^4−x+8)−(7x^5+2x^4−12+6x−5x^3+x^2)

Distribute the minus sign

(2x^5+x^3−3x^4−x+8)−7x^5-2x^4+12-6x+5x^3-x^2

Put them in order from largest exponent to smallest exponent

2x^5−7x^5−3x^4-2x^4+5x^3+x^3-x^2-6x−x+8+12

Combine like terms

-5x^5 -5x^4 +6x^3 -x^2 -7x +20

Standard form is from largest exponent to smallest exponent

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50,000 contestants participate in an on-line game. The game randomly eliminates 20% of the contestants each day. Determine the n
irga5000 [103]

Answer:10,486 contestants

Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

That is, (20/100)×50,000 = 10,000

Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

Contestants= 40,000

20% removed

That is (20/100)×40000=8000

Balance =40000-8000=32,000

Third day:

Contestants= 32000

20% removed

That is (20/100)×32000=6400

Balance =32000-6400=25,600

Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

20% removed

That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

20% removed

That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

20% removed

That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

6 0
3 years ago
Find the LCM of k^2 + 3k + 2 and 2k^2 + 14k + 20.
Airida [17]

Answer:

  C.  2(k +2)(k +5)(k +1)

Step-by-step explanation:

The LCM will be the product of unique factors.

  (k^2 + 3k + 2)=(k+1)(k+2)\\(2k^2 + 14k + 20)=2(k+2)(k+5)

The unique factors are 2, (k+1), (k+2), (k+5), so the LCM is their product:

  2(k+1)(k+2)(k+5) . . . . matches choice C

3 0
3 years ago
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igor_vitrenko [27]

Answer:

D, 25h

Step-by-step explanation:

15 is just the tax. For example, if someone spends 2 hours getting tutored, the n that person pays 2 hours multiplied by 25, which is 50 bucks in total.

6 0
3 years ago
Read 2 more answers
What is the answer to 7(2e−1)−3=6+6e
ludmilkaskok [199]
<span>Simplifying
7(2e + -1) + -3 = 6 + 6e

Reorder the terms:
7(-1 + 2e) + -3 = 6 + 6e
(-1 * 7 + 2e * 7) + -3 = 6 + 6e
(-7 + 14e) + -3 = 6 + 6e

Reorder the terms:
-7 + -3 + 14e = 6 + 6e

Combine like terms: -7 + -3 = -10
-10 + 14e = 6 + 6e

Solving
-10 + 14e = 6 + 6e

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Add '-6e' to each side of the equation.
-10 + 14e + -6e = 6 + 6e + -6e

Combine like terms: 14e + -6e = 8e
-10 + 8e = 6 + 6e + -6e

Combine like terms: 6e + -6e = 0
-10 + 8e = 6 + 0
-10 + 8e = 6

Add '10' to each side of the equation.
-10 + 10 + 8e = 6 + 10

Combine like terms: -10 + 10 = 0
0 + 8e = 6 + 10
8e = 6 + 10

Combine like terms: 6 + 10 = 16
8e = 16

Divide each side by '8'.
e = 2

Simplifying
<span>e=2
</span></span>
(sorry, i went into depth)
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3 years ago
Find the value of Tan O for the angle shown.
Maru [420]
C because that’s what it is
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3 years ago
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