This question is based on least common multiple method.
As given in the question,
Aunts are taking pictures in group of = 5
Uncles are taking pictures in group of = 10
So we have been asked what is the minimum number of aunts Sana have.
As we have been given that the number of aunts and uncles is equal so to find the minimum number of aunts we will apply the least common multiple method.
So we get LCM of 5,10 as 10
Hence there are minimum 10 aunts.
4 classes, $52
Do it the long way to check
This may not be very pretty.
(2x + 5) * (2x + 5) expanded is (use foil)
F = 4x^2
O = 2x * 5 = 10x
I = 2x + 5 = 10x
L = 25
Total = 4x^2 + 20x + 25
(x + 3)(x + 3) = x^2 + 6x + 9 by the same method
(2x + 7)(2x + 7) = 4x^2 + 28x + 49 Same method.
4x^2 + 20x + 25 + x^2 + 6x + 9 = 4x^2 + 28x + 49
5x^2 + 26x + 34 = 4x^2 + 28x + 49 Collect everything on the left.
x^2 - 2x - 15 = 0
(x - 5)(x + 3) = 0
x + 3 will have no meaning.
x - 5 = 0
x = 5
2x + 5 = 2*5 + 5 = 15
x + 3 = 5 + 3 = 8
2x+ 7 = 2*5 +7 = 17
Check
15^2 + 8^2 = 17^2
225 + 64 = ? 289
289 = 289
a = 15 <<<<< answer
b = 8 <<<<< answer
c = 17 <<<<< answer
Answer:
340 in.
Step-by-step explanation:
L x W x H
17 x 4 x 5 = 340
