Cot(3x)=3^(1/2)
cot(x)= cos(x)/sin(x)
cot(3x)= cos(3x)/sin(3x)
look at a unit circle chart
find a value for cos that has sqrt(3) in it
which one will reduce so that the cos/sin will equal sqrt(3)?
pi/6 radians
now cot(3x) implies that x is one third this value
pi/18 is the answer
Answer:
We have that:

And we want to find the value of g(4)
Then we are evaluating the function g(x) in x = 4, this means that we need to locate all the "x" in g(x), and replace them by 4.
If we do that, we get:

Now we can just solve this to get:

Step-by-step explanation:
5x90=450
700-450=250
250/5=50
50 more tickets.
i don't know if that's in an inequality form or not. but that's how many tickets
123a
123q
123w
123e
123r
123t
123y
123u
123i
123o
123p
123s
123d
123f
123g
123h
123j
123k
I thought this would be easy lol, I tried, sorry for not getting an answer
Answer:

Area is greater than
sq ft.
Step-by-step explanation:
Length of rectangular sign board =
ft
Width of rectangular sign board =
ft
Area of a rectangle is given by the formula:

To find the area, we are going to multiply
with
.
is greater than 1.
Therefore the multiplication will be greater than
.
Hence, we can say that area will be greater than
sq ft.
Area of the sign:
