All categories

3 years ago

Solve the system of equations algebraically: y = x+5 y = -2x

Mathematics

2 answers:

Verizon [17]3 years ago

4 0

Answer:

x = -5/3

y = 10/3

Step-by-step explanation:

y = x+5

y = -2x

y = x+5

-2x = x + 5

-3x = 5

x = -5/3

y = x+5

y = -5/3 + 5

y = 10/3

Mashutka [201]3 years ago

3 0

Answer: X= -5/3
-2x=x+5
-3x=5
X=-3/5

You might be interested in

A four member work crew needed new equipment. Boots cost 75 each, safety vest cost 15 each and hard hats cost 30 each. What is t

Olenka [21]

Multiply 75*4(300), 15*4(60), and 30*4(120) then add all the answers up (480)

7 0

3 years ago

The first equation in a system is 5x+2y=-4. Which equation gives a system with no solution.

abruzzese [7]

Answer:

= 0.8 + -0.4y

Step-by-step explanation:

Simplifying

5x + 2y = 4

Solving

5x + 2y = 4

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.

5x + 2y + -2y = 4 + -2y

Combine like terms: 2y + -2y = 0

5x + 0 = 4 + -2y

5x = 4 + -2y

Divide each side by '5'.

x = 0.8 + -0.4y

8 0

4 years ago

What is w(53)is equal to

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

The question is slightly ambiguous. The problem is, do you find the first 40 hours using 10x and then the second equation using x >40. I don't think so, but it should be made clear. It turns out that the first 40 hours does equal 400 so that you can use the second expression with no worries.

w(53) = 15(53 - 40) + 400

w(53) = 15(13) + 400

w(53) = 195 + 400

w(53) = 595

5 0

3 years ago

A total of 937 people attended the play admission was $2.00 for adults and $0.75 for students. The total ticket sales amounted t

mamaluj [8]

612 students attended and 325 adults attended the play

<h3><u>Solution:</u></h3>

Let "s" be the number of students attended the play

Let "a" be the number of adults attended the play

Cost of 1 adult ticket = $ 2

Cost of 1 student ticket = $ 0.75

<em><u>Given that total 937 people attended the play</u></em>

number of students + number of adults = 937

s + a = 937 ---------- eqn 1

<em><u>The total ticket sales amounted to $1,109</u></em>

number of adults x Cost of 1 adult ticket + number of students x Cost of 1 student ticket = 1109

$a \times 2 + s \times 0.75 = 1109$

2a + 0.75s = 1109 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

s = 937 - a -------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

2a + 0.75(937 - a) = 1109

2a + 702.75 - 0.75a = 1109

1.25a = 1109 - 702.75

1.25a = 406.25

$a = \frac{406.25}{1.25}$

From eqn 3,

s = 937 - 325

Thus 612 students attended and 325 adults attended the play

3 0

3 years ago

HELP PLEASE!

Dennis_Churaev [7]

Hello,

This answer may be wrong.. But I'm trying to make sure it's not!!

C. 1,008 :)

8 0

3 years ago

Read 2 more answers