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denis23 [38]
3 years ago
9

Show all work to multiply (3+ /(-16))(6-/(-64))

Mathematics
2 answers:
Artemon [7]3 years ago
7 0

Answer:

undefined

Step-by-step explanation:

negative square root does not exist in set of real numbers

Reil [10]3 years ago
6 0

Answer:

=50

Step-by-step explanation:

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A bowl contains 25 balls numbered 1 to 25. A ball is drawn and its number is noted. Without replacing the first ball, another ba
bazaltina [42]

13  balls are odd in 25

1st pick = 13/25 probability of picking an odd

2nd pick = 12/24 = 1/2 probability

13/25 x 1/2 = 13/50 probability

Answer would be 13/50


6 0
3 years ago
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Write a real-world scenario for the equation 10x + 2 = 8x + 8. Solve the equation.
Allisa [31]

Answer:

3

Step-by-step explanation:

Frank wants to find a number that is multiplied by 10 is 2 less than 8 times the number plus 8.

Hope that helps :)

5 0
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Complete this activity.<br> Given: f(x) = x + 2 and h(x) = 1/x-1 <br> 2f(x) - h(x) =
gayaneshka [121]
X plus 4 -1x there, that's the next sequence


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4 years ago
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brianna choclotate chip cookies recipe will make about 3 dozen cholotate chip cookies . The recipe calls for 2 1/4 cups of flour
dybincka [34]
So if she uses 2 1/4 for 3/8 thats 5/8 more which is 62.5% so 2 1/4+62.5 of 2 1/4 so 1 7/20+2 1/4 to get 3 3/5.
4 0
3 years ago
Factorise x^12 y^4 - x^4 y^12<br><br>PLEASE PLEASE explain in step by step Pleasseeeeee​
QveST [7]

Answer:

Step-by-step explanation:

First, look at your terms. You have two terms and two variables in each. So they can be factored out because you can distribute them back in easily.

Focus one variable first, x. You cant factor an x^12 out of an x^4. You can, but you really don't want to, it'll turn your problem into a mess. So the only thing you can do is factor out the lower exponent, x^4.

x^4(x^8y^4-y^1^2)

We arent done yet because the terms still share the y variable. You cant factor a y^12 from a y^4. This is the same problem with the x variable. So take out the lower one, y^4.

x^4y^4(x^8-y^8)

8 0
3 years ago
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