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3 years ago

13

Green yellow purple or grey pins in a bag.

2 answers:

NemiM [27]3 years ago

5 0

Answer:

i think purple is nice

Step-by-step explanation:

oops

DiKsa [7]3 years ago

3 0

Answer:

yellow

Step-by-step explanation:

I choose yellow because it's a beautiful spring color

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Rewrite f(x) = –2(x − 3)2 + 2 from vertex form to standard form. pleae help.

-Dominant- [34]

F(x) = -2(x - 3)² + 2
f(x) = -2(x - 3)(x - 3) + 2
f(x) = -2[x(x - 3) - 3(x - 3)] + 2
f(x) = -2[x(x) - x(3) - 3(x) - 3(-3)] + 2
f(x) = -2(x² - 3x - 3x + 9) + 2
f(x) = -2(x² - 6x + 9) + 2
f(x) = -2(x²) - 2(-6x) - 2(9) + 2
f(x) = -2x² + 12x - 18 + 2
f(x) = -2x² + 12x - 16

7 0

3 years ago

Read 2 more answers

An airplane is flying from New York City to Los Angeles. The distance it travels in miles, d is 0.15 per second of time, t.

garik1379 [7]

Here the function given by

f(d)=0.15t

Now

f(1):-

$\\ \sf\longmapsto f(1)=0.15(1)=0.15m$

$\\ \sf\longmapsto f(2)=0.15(2)=0.3m$

6 0

3 years ago

2. Find the product (2x + 3)(3x - 2).

eimsori [14]

Answer:

6x² + 5x - 6

Step-by-step explanation:

Given

(2x + 3)(3x - 2)

Each term in the second factor is multiplied by each term in the first factor, that is

2x(3x - 2) + 3(3x - 2) ← distribute both parenthesis

= 6x² - 4x + 9x - 6 ← collect like terms

= 6x² + 5x - 6

6 0

3 years ago

Read 2 more answers

Please help soon algebra 1 problem in screenshot

Luda [366]

36 actually, I counted it myself

3 0

4 years ago

Simplify tan9x-tan5x / 1+tan9xtan5x<br> (SHOW WORK)

Charra [1.4K]

Answer:

The simplest form is tan(4x)

Step-by-step explanation:

* Lets revise the identity of the compound angles

- $tan(a+b)=\frac{tan(a)+tan(b)}{1-tan(a)tan(b)}$

- $tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}$

* Lets solve the problem

- Let 9x = 5x + 4x

∴ tan(9x) = tan(5x + 4x)

- Use the rule of the compound angle

∵ $\frac{tan(9x)-tan(5x)}{1+tan(9x)tan(5x)}$ ⇒ (1)

∵ $tan(5x+4x)=\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}$ ⇒ (2)

∵ tan(9x) = equation (2)

- Substitute (2) in (1)

∴ $\frac{\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}-tan(5x)}{1+(\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)})tan(5x)}$

- Multiply up and down by (1 - tan(5x)tan(4x))

∴ $\frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}$

- Simplify up and down

∴ $\frac{tan(5x)+tan(4x)-tan(5x)+tan^{2}(5x)tan(4x)}{1-tan(5x)tan(4x)+tan^{2}(5x)+tan(5x)tan(4x) }$

∴ $\frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}$

- Take tan(4x) as a common factor up

∴ $\frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}$

- Cancel [1 + tan²(5x)] up and down

∴ The answer is tan(4x)

4 0

4 years ago