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stiv31 [10]
3 years ago
12

How will you remember what changes when reflecting across the x-axis?

Mathematics
1 answer:
natulia [17]3 years ago
5 0

Answer: When you reflect a point across the x-axis the x-coordinate remains the same, but the y-coordinate is transformed into its opposite

Step-by-step explanation:

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the vertex is the lowest point

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there is no question/angle so i don't know how to help you

7 0
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Can u guys help me with this... Thanks ❤️
lianna [129]

Answer:

90 divided by 15

Step-by-step explanation:

= 6

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I really need help on all of them, I will give out brainliest to one answer and ten points to both
tangare [24]

Answer:

1. 1/2, 2. 2, 3. 1/-3, 4. -2

Step-by-step explanation:

1) I know that the equation for slope is y2-y1/x2-x1. For number one I first found two points of the graph which is (0,3) and (2,4) (not sure if I see it correctly, its kind of blurry). I decided that (0,3) would be my y1 and x1 and (2,4) will be my y2 and x2. I later plugged the number in the equation and got 4-3/2-0 which the answer turns out to be 1/2.

2) For the rest of the questions it is kinda the same business as question 1. For question two I chose two points out of the table which wrer (-1, -12) and (1,-8) and plugged them into the equation and got -8-(-12)/1-(-1) which the answer turns out to be 2.

3) similar to question 2. The two points(2,-6) and (-4,-3) are given to you. so I plugged them in again and got -3-(-6)/-4-2 which the answer turns out to be 3/-6 into 1/-3.

4) Same with question 1 find two points of the graph. I chose (0,3) and (1,1) (again might not be accurate it's kind of blurry) I plugged them into the equation again and got 1-3/1-0 which equals -2.

Just always remember y2-y1/x2-x1=m is the equation for slope.

(m is the variable for slope)

Hoped this helped you : )

3 0
3 years ago
Y=sech(tan‐¹x) find the derivative ​
Klio2033 [76]

Recall that

d/dx sech(x) = - sech(x) tanh(x)

d/dx tan⁻¹(x) = 1/(1 + x²)

Then by the chain rule,

dy/dx = - sech(x) tanh(x) / (1 + x²)

8 0
3 years ago
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