If you factor the denominator of the left multiplicand...
[(a-4)(a+3)]/[a(a-4)] you can see that the (a-4)s cancel out leaving:
(a+3)/a
now you have
(a+3)/a * 2a^3/((a+3)(a-1)) so the (a+3)s cancel out leaving:
1/a * 2a^3/(a-1) which is:
2a^3/(a(a-1)) so now a^1 cancel leaving
2a^2/(a-1)
Answer:
Option A, Trapezoid
Step-by-step explanation:
<em>Since there is two parallel sides and two nonparallel, that means it is a trapezoid.</em>
Answer: Option A, Trapezoid
Answer:I don’t speak Spanish .
Step-by-step explanation:
It is not a function—an element from the domain is paired with more than one element from the range. Specifically, the input value of 4 corresponds to two output values: 5 and -4.
A function can only take on one output for each input. It only takes one input value to associate with more than one output value to be invalid as a function.
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