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Vesna [10]
3 years ago
10

Richard deposits $237.95 every month into his mortgage. At the end of 30 years, he has a balance of $183,710.77. What interest h

as accrued (been earned) over 30 years?
Mathematics
1 answer:
77julia77 [94]3 years ago
3 0

Answer:

$98,048.77

Step-by-step explanation:

First you want to find out how much he has put in without interest so you would do 237.95*12 to figure out how much he puts in per year then times that number by 30 to figure out how much he has put in in total, after this you subtract this total from the 183,710.77 to get the total amount of interest

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4 0
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4 0
3 years ago
If you can explain your answer that’d be great!! Thank you!
Rasek [7]

Answer:

A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}

Step-by-step explanation:

This half life exponential decay equation goes by the formula:

A(t)=A_{0}e^{kt}

Where

k=\frac{ln(\frac{1}{2})}{Half-Life}

Since half life is given as 22, we plug that into "Half-Life" in the formula for k and then plug in the formula for k into the exponential decay formula:

So,

k=\frac{ln(\frac{1}{2})}{Half-Life}\\k=\frac{ln(\frac{1}{2})}{22}

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A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}

third choice is correct.

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