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3 years ago

10

Richard deposits $237.95 every month into his mortgage. At the end of 30 years, he has a balance of $183,710.77. What interest h

as accrued (been earned) over 30 years?

1 answer:

77julia77 [94]3 years ago

3 0

Answer:

$98,048.77

Step-by-step explanation:

First you want to find out how much he has put in without interest so you would do 237.95*12 to figure out how much he puts in per year then times that number by 30 to figure out how much he has put in in total, after this you subtract this total from the 183,710.77 to get the total amount of interest

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I need help with Question 14 . I need to submit it by monday...<br> Pls help

GaryK [48]

Answer:

Distance between A and B is 5400 meters

Step-by-step explanation:

Consider "D" the letter to identify distance between A and B

Let's use "t" to identify the time of the first encounter (Devi and Kumar), and create an equation that states that the distance covered by Devi (at 100 m/min) in time "t", is equal to the total distance D minus what Kumar has covered at his speed (80 m/min) in that same time:

Recall that distance equals the speed times the time:

distance= speed * time

First encounter:

100 * t = D - 80 * t

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Not, 6 minutes later (at time t+6) , Devi and Li Ting meet .

Then for this encounter the distance covered by Devi equals total distance d minus the distance covered by Li Ting:

100 *(t+6) = D - 75 * (t+6)

100 t + 600 = D - 75 t - 450

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Now, let's equal equation (1) to equation (2), since D should be the same:

180 t = 175 t + 150

5 t = 150

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3 years ago

Find the perimeter of the rectangle.<br> A 10.5 m<br> B 17 m<br> C 21 m<br> D 34 m

marusya05 [52]

17........................

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3 years ago

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PLEASE HELP QUICK! I'M OFFERING 25PTS & BRAINLIEST ANSWER (Its only worth 10pts) I just need this done PLEASE SHOW YOUR WORK

LenaWriter [7]

QUESTION 1

The dimensions of the rectangular blanket are;

$l = (3x + 7)cm$

and

$w = (2x - 3)cm$

The perimeter is given by,

$p= 2w + 2l$

We substitute the dimensions to obtain,

$p = 2(2x - 3) + 2(3x + 7)$

Expand bracket to get,

$p = 4x - 6 + 6x + 14$

This simplifies to
$p =( 10x + 8 )cm$

QUESTION 2

When

$x = 4$
The perimeter becomes

$p =( 10(4) + 8 )cm$

$p =( 40 + 8 )cm$

$p =48cm$

QUESTION 3

Area is given by

$A=l \times w$
$A=(3x + 7)(2x - 3)$

We expand to get,

$A=6 {x}^{2} - 9x + 14x - 21$

This gives us,

$A=(6 {x}^{2} + 5x - 21) {cm}^{2}$

QUESTION 4

If
$x = 4$
Then the area becomes,

$A=6 {(4)}^{2} - 9(4)+ 14(4) - 21$

$A=6 \times 16 - 36+ 56- 21$

$A=96 - 36+ 56- 21$

$A=95 {cm}^{2}$

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When the length of the blanket is 5cm longer, then the length of the new blanket becomes

$l = (3x + 7 + 5)$

$l = (3x + 12)cm$

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$w = (2x - 3)cm$

The perimeter of the new blanket is

$p = 2(3x + 12) + 2(2x - 3)$

This implies that,

$p = 6x + 24+ 4x - 6$

$p = 10x +18$

Comparing to the old perimeter which is

$p = 10x +8$ ,

The perimeter changes by 10 units

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Gemiola [76]

8.33333333 repeat.
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