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Tcecarenko [31]
3 years ago
13

How many terms in 2-8+22 A. 1 B. 2 C. 3 D. 26

Mathematics
1 answer:
natima [27]3 years ago
4 0

Answer:

6 is the answer.

is it right

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Write a polynomial function of least degree with integral coefficients that has the given zeros.
densk [106]
The zeroes are
0, -5, 3 + i (and its conjugate)

The factors are
x (x + 5) (x - (3 + i)) (x - (3 - i))
Expanding...
(x² + 5x)((x - 3) - i) ((x - 3) + i)
(x² + 5x)((x - 3)² - i²)
(x² + 5x)(x² - 6x + 9 - (-1))
(x² + 5x)(x² - 6x + 10)
x⁴ - 6x³ + 10x² + 5x³ - 30x² + 50x
x⁴ - x³ - 20x² + 50x
4 0
3 years ago
1 . Evaluate 3a - 12 divided by a for a =4 2. Evaluate 3x- 2y , if x= 5 and y =3
ziro4ka [17]
This is how I understood the question

Hope I helped!

3 0
3 years ago
Consider f and c below. f(x, y) = (3 + 4xy2)i + 4x2yj, c is the arc of the hyperbola y = 1/x from (1, 1) to 3, 1 3 (a) find a fu
irga5000 [103]
We want to find a scalar function f(x,y) such that \nabla f(x,y)=\mathbf f(x,y)=\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j.
So we need to have
\dfrac{\partial f}{\partial x}=3+4xy^2
Integrating both sides with respect to x gives
f(x,y)=3x+2x^2y^2+g(y)
Differentiating with respect to y gives
\dfrac{\partial f}{\partial y}=4x^2y+\dfrac{\mathrm dg}{\mathrm dy}=4x^2y\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C
So we find that
f(x,y)=3x+2x^2y^2+C
By the fundamental theorem of calculus, we then know the line integral depends only on the values of f(x,y) at the endpoints of the path. Therefore

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(3,\frac13\right)-f(1,1)=11-5=6
4 0
3 years ago
Write an equation for the nth term of the arithmetic sequence. Then find a50.
julia-pushkina [17]

Step-by-step explanation:

Since the sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

a = 1/3

d = 1/2 - 1/3 = 1/6 or 2/3 - 1/2 = 1/6

Substitute the values into the above formula

That's

<h3>A(n) =  \frac{1}{3}  + (n - 1) \frac{1}{6}  \\  =  \frac{1}{ 3}  -  \frac{1}{6}   +  \frac{1}{6} n</h3>

So the nth term of the sequence is

<h3>A(n) =  \frac{1}{6}  +  \frac{1}{6}n</h3>

For a50 since we are finding the 50th term

n = 50

So we have

<h3>A(50) =  \frac{1}{6}  +  \frac{1}{6} (50) \\  =  \frac{1}{6}  +  \frac{25}{3}</h3>

We have the final answer as

<h3>A(50) =  \frac{17}{2}</h3>

Hope this helps you

4 0
3 years ago
Please help! Forgot to do homework and I really need help! WORTH 30 POINTS!
stepan [7]

Answer:

M=-4

A=-16

K=1

X=9

Q=-6

V=2

7 0
3 years ago
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