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Ber [7]
3 years ago
4

Identify the plasmid that must contain the CD3γ core promoter sequence but the fewest or no negative regulatory sequences. Based

on the data in Figure 2, describe the most likely cause of the variation in luciferase activity among the cells that contain plasmids pCD3γ-419 , pCD3γ-309 , pCD3γ-239 , and pCD3γ-199 . Calculate the approximate percent increase in luciferase activity between cells containing plasmid pCD3γ-59 and cells containing plasmid pCD3γ-149 . Round to the nearest whole number.
Biology
1 answer:
Papessa [141]3 years ago
8 0

Answer:

Check the explanation

Explanation:

The luciferase mRNA is translated to its corresponding protein in the ribosome which is present in the cytoplasm of the cell.

In the cytoplasm, the chain of ribosome sits on the mRNA and forms a structure called a polysome. This helps in the fast synthesis of protein.

The three-nucleotide genetic code in the mRNA which is being read by the ribosome dictates the correct arrangement of amino acids through particular tRNA.

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Gynecomastia is a problem relatively common in the population, and there are three prevalence peaks throughout life:

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3 years ago
Identify the six different phases by name. Record characteristics that you used to determine what the order is for each phase. (
vesna_86 [32]

Answer:

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Explanation:

6 0
3 years ago
Describe some advantages and disadvantages of solar energy.
blagie [28]
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3 years ago
A geneticist is studying two traits in the fruit fly - eye color and wing shape. They perform a dihybrid cross. If the genes for
Len [333]

Answer:

3/16

Explanation:

<u>According to Mendel's law of independent assortment of genes, when a dihybrid cross involves two genes that assort independently and one of the parents is dominant for the two genes and the other is recessive, the phenotypic ratio of the offspring at F2 would be 9:3:3:1</u>. The proportion of the offspring with the dominant parental traits would be 9/16, those with the recessive parental traits would be 1/16, while those with mixed traits would be 3/16 each.

Assuming the eye color is represented by E and the wing shape is represented by W. At F2

     EeWw    x    EeWw

E_W_ - 9/16 (dominant for both eye color and wing shape)

E_ww - 3/16 (dominant for eye color and recessive for wing shape)

eeW_ - 3/16 (recessive for eye color and dominant for wing shape)

eeww - 1/16 (recessive for both eye color and wing shape)

<em>Hence, the proportion of the offspring with dominant phenotype for eye color and recessive phenotype for wing shape would be </em><em>3/16.</em>

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