Answer:
93
Step-by-step explanation: The first term of AP is -5 and second term means -3.
Common difference(d) = second term - first term
d = (-3)-(-5)
d= 2
Now using the formula of nth T
n
=a
1
+(n−1)d
Here a
1
=−5,n=50,d=2
Puting these values in the formula of of nth term we get
a
n
=−5+(50−1)2
a
n
=−5+98
a
n
=93
Answer:
The answer is "MS and QS".
Step-by-step explanation:
Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.
As NR and MQ bisect each other at S
⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e MS=SQ
In ΔMNS and ΔQNS
MN=QN (∵ MNQ is isosceles triangle)
∠NMS=∠NQS (∵ MNQ is isosceles triangle)
MS=SQ (Given)
By SAS rule, ΔMNS ≅ ΔQNS.
Hence, segments MS and SQ are therefore congruent by the definition of bisector.
The correct option is MS and QS
<h2>
Answer:</h2><h2>3s + 4</h2><h2 /><h2>Hope this helps!!!</h2>
10% of the 50 were red.
10% * 50
(10/100) * 50
(1/10) * 50
= 5
5 were red.
Answer:
The Answer is 96 .
Step-by-step explanation:
i hoped it's helpful
thank you ☺️☺️☺️