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hammer [34]
3 years ago
8

Gi finds some dimes and quarters in her backpack. There are 5 fewer quarters than dimes. The total value of the coins is $1.20.

How many of each coin does Gi find? Select the answers from the drop-down menus to correctly complete the statement.
Gi finds ___ dimes and ____quarters.
Mathematics
1 answer:
just olya [345]3 years ago
3 0
G finds 7 Dimes and 2 Quarters. 
Hope this helps!
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25, 8, 10, 35, 5, 45, 40, 30, 20 What is the upper quartile of the data set above?A.35
Vlada [557]
<span>An upper quartile is the range of numbers above the median in a set. Thus, the numbers have to be rearranged mentally or on paper. Fortunately, there are an odd set of numbers, so one number, 25, is the median. The upper quartile is 30, 35, 40, 45.</span>
6 0
2 years ago
What’s the correct answer for this question?
xxMikexx [17]

Answer:

12.22

Step-by-step explanation:

To find HI, you have to use tangent. tanx=\frac{opposite}{adjacent}

tan(42°)=\frac{11}{HI} , then you multiply HI to both sides of equation and divide tan(42).

To get <em>HI</em>=\frac{11}{tan(42)}

Which makes HI equal 12.2167

5 0
2 years ago
PLEASE HELP
kolbaska11 [484]

Answer:

  • a) P(x) = 32000*1.04^x
  • b) $37435
  • c) During year 7

Step-by-step explanation:

<u>Given</u>

  • Initial pay = $32000
  • Increase rate = 4%

a. <u>Formula</u>

  • P(x) = 32000*1.04^x

b. Year 5 is after 4 years, so we are looking for the value of P(4)

  • P(4) = $32000*1.04^4 = $37435

c. <u>P(x) = 40000, x = ?</u>

  • 40000 = 32000*1.04^x
  • 1.04^x = 40000/32000
  • 1.04^x = 1.25
  • log 1.04^x = log 1.25
  • x = log 1.25 / log 1.04
  • x = 5.69, this is 6 years after

The required number of the years is 6 + 1 = 7

3 0
2 years ago
HELP ME PLZZ I NEED HELP WITH THIS!!
VARVARA [1.3K]

Answer:

a

Step-by-step explanation:

7 0
2 years ago
Help!!! Quick!!! Plzzzzz!!!
max2010maxim [7]

Answer:

x = -8

y = 9

Step-by-step explanation:

to solve this expression using simultaneous equation, we would say let

y =9............................................. equation 1

 6x + 5y =-3............................................equation 2

substitute equation 1 into equation 2

-3 = 6x + 5y............................................equation 2

6x + 5(9) = -3

6x + 45 = -3

collect the like terms

6x = -3-45

6x = -48

divide both sides by the coefficient of x which is 6

6x/6 = -48/6

x = -8

therefore y = 9

x = -8

4 0
3 years ago
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