Answer:

Step-by-step explanation:
we are given

we can simplify left side and make it equal to right side
we can use trig identity


now, we can plug values

now, we can simplify



now, we can factor it

![\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28sin%28a%29%2Bcos%28a%29%29%5B3-4%28sin%5E2%28a%29%2Bcos%5E2%28a%29-sin%28a%29cos%28a%29%5D%7D%7Bsin%28a%29%2Bcos%28a%29%7D%20)
we can use trig identity

![\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28sin%28a%29%2Bcos%28a%29%29%5B3-4%281-sin%28a%29cos%28a%29%5D%7D%7Bsin%28a%29%2Bcos%28a%29%7D%20)
we can cancel terms

now, we can simplify it further




now, we can use trig identity

we can replace it

so,

Answer:
Step-by-step explanation:
1. 5
2. -9
3. -4
4. 4 > .25
5. 0.142 < 7
6. -8 = -8
Hello,
function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};
if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};
// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);
Answer:
check online for more information
Answer:
The probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license is 0.32.
Step-by-step explanation:
Denote the events as follows:
<em>X</em> = a fisher at Clearwater Park had a fishing license
<em>Y</em> = a fisher at Mountain View Park had a fishing license
The two events are independent.
The information provided is:
n (X) = 48
n (X') = 32
n (Y) = 72
n (Y') = 18
Then,
N (X) = n (X) + n (X')
= 48 + 32
= 80
N (Y) = n (Y) + n (Y')
= 72 + 18
= 90
Compute the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license as follows:


Thus, the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license is 0.32.