<span>You are given a rectangular picture measuring 8 inches by 7 inches. Also, Alistair wants this to be framed and that the total area is 34 square inches. The width of the frame is x inches. To solve the dimension of the frame with value of x we have:
We have to assume that x here will be equal to all sides of the frame and so, using the area of the rectangle, we can model the equation like this:
A = LW (where A is the area, L is the length and W is the width)
36 = (8 - x)(7 - x)
36 = 56 - 8x - 7x + x</span>²
<span>x</span>² - 15x +20 = 0 → model of our equation and in quadratic form
x² - 15x + 20 = 0
using a calculator, x = 1.48 inches
<span>
3.Use the equation you created in part A to find the width of the picture frame</span>
Answer:
7/20
Step-by-step explanation:
Hope this help and have a great day!!!
IF you are solving for d:
isolate the D, do the opposite of PEMDAS.
-d/6 + 12 = -7
(subtract 12 from both sides)
-d/6 + 12 (-12) = -7 (-12)
-d/6 = -19
(multiply 6 to both sides)
-d/6(6) = -19(6)
-d = -19(6)
-d = -144
-d/-1 = -144/-1
d = 144
hope this helps
Hey there!
To find the value of an angle in a triangle, you need to add the 3 angles. You have angles with 55 degrees, 65 degrees, and x degrees. Put this into an equation. The equation would be 55+65+x=180. Simplify to get 120+x=180. You need to isolate x, so subtract 120 from both sides to get x=60. So the value of x is 60 degrees.
I hope this helps!
Answer:
x²-6x+y²-4y=-4
Step-by-step explanation:
We know the circle equation stands like this:
(x-a)² + (y-b)² = R²
and (a,b) is center
and R stands for Radius
so in this case:
center = (3,2)
R = 3
So
(x-3)² + (y-2)² = 9
x²-6x+9 + y²-4y+4=9
x²-6x+y²-4y=-4
