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anastassius [24]
2 years ago
8

Ratio of 14 inches to 3 feet

Mathematics
1 answer:
jeka57 [31]2 years ago
4 0

Answer:

14/3 or 14:3

explanation of LIFE jk jk

I am very sorry if I am wrong

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What is 87.252 dividend by 2.2 I am not sure how to do the work
WARRIOR [948]

Answer:

39.66

Step-by-step explanation:

If the divisor is not a whole number, move decimal point to right to make it a whole number and move decimal point in dividend the same number of places.

Divide like you usually do

Put decimal point directly above decimal point in the dividend.

Check your answer.


7 0
3 years ago
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What is 1/10 of 1000
mylen [45]
\frac{1}{10} *1000= \frac{1000}{10} =100
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An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
Find the lateral surface area of the figure.
Brut [27]

Surface area of the cylinder = 816.4 sq. ft.

Solution:

Height of the cylinder = 21 ft

Diameter of the cylinder = 10 ft

Radius of the cylinder = 10 ÷ 2 = 5 ft

Use the value of \pi = 3.14

Surface area of the cylinder = 2 \pi r h+2 \pi r^{2}

Substitute the given values in the surface area formula, we get

Surface area of the cylinder $=2\times3.14\times 5\times 21+2 \times3.14\times 5^2

                                               =659.4+157

                                               =816.4 ft²

Hence the surface area of the cylinder is 816.4 sq. ft.

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What is the area of triangle ABC?
erica [24]

Answer:

what is the area of triangle ABC choices

35 square unit

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