If you begin with the graph for f(x) and then substitutde x+3 for x, the effect on the graph will be to move the whole graph 3 units to the left.
Given that (-9,-1) is on the graph of f(x), and that we are to move the entire graph 3 units to the left, then the coordinate -9 becomes -9-3, or -12: (-12,-1).
A vertical stretch by a factor of 2 of F(x) = -2|x-2|+4 would result in the revised function G(x) = -4|x-2|+4. The vertex would stay in the same place (2,4).
The best and most correct answer providedfrom your question about the entrance examination paper is the second option which is 2,250. The problem can be solved by:
3-1-1 : 5c3*5c1*5c1 *3!/2! = 750
<span>2-2-1 : 5c2*5c2*5c1 *3!/2! = 1500
</span>
Adding the two answers:
750 + 1500 = 2250
I hope it has come to your help.
15 times 6 = 90, 7 times 8 = 56, 9 times 3 = 37 or all of them together equals 153 :)
Answer:
4
Step-by-step explanation:
split it horizontally, vertically and diagonally twice.